小编use*_*120的帖子

将STD_LOGIC连接到一位STD_LOGIC_VECTOR

我正在使用Xilinx ISE,并使用CORE Generator和Architecture Wizard生成了内存。

问题在于它创建了一个写使能信号(wea)作为STD_LOGIC_VECTOR(0到0),并导致类型不匹配:

第###行:encnt附近类型错误;当前类型为std_logic; 预期的类型std_logic_vector

如何将encntstd_logic转换为一点std_logic_vector?

(ISE不允许我从内存文件中更改Wea。)

casting vhdl xilinx-ise

2
推荐指数
1
解决办法
3219
查看次数

vhdl代码理解,如果存在关于可能无限循环的modelsim错误

--
-- VHDL Architecture di_lib.ShiftRegister1.ShiftRegister1
--
-- Created:
--          by - 294162.UNKNOWN (VD1210)
--          at - 14:19:36 10-04-2015
--
-- using Mentor Graphics HDL Designer(TM) 2010.2a (Build 7)
--
LIBRARY ieee;
USE ieee.std_logic_1164.all;

LIBRARY WORK;
USE WORK.CALC_PKG.ALL;
LIBRARY di_lib;
USE di_lib.calc_pkg.all;
USE ieee.NUMERIC_STD.all;

ENTITY ShiftRegister1 IS
   PORT( 
      d_out       : OUT    Std_Logic_Vector (7 DOWNTO 0);
      multiplexer : IN     Std_Logic_Vector (7 DOWNTO 0);
      carry       : IN     std_logic;
      load_out    : IN     std_logic;
      f_code      : IN     std_logic_vector (2 DOWNTO 0);
      out_loaded  : OUT    std_logic …
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vhdl

1
推荐指数
1
解决办法
1681
查看次数

Kotlin泛型方法和继承

在我的代码中,我想在抽象类中创建一个方法,它返回一些Observable.然后,这个抽象类的实现将返回某个(指定)类型的Observable.不幸的是,Android Studio将在实现方法()中返回错误"类型不匹配":

  • 预期:可观察
  • 找到:Observable <{package} .DrawerItemEntity>

我的MockDrawerList.getList()回报Observable<DrawerItemEntity>

请专注于execute()buildUseCaseObservable

抽象类

public abstract class UseCase(threadExecutor: ThreadExecutor,
    postExecutionThread: PostExecutionThread) {

    private val threadExecutor: ThreadExecutor
    private val postExecutionThread: PostExecutionThread

    private var subscription: Subscription = Subscriptions.empty()

    init {
        this.postExecutionThread = postExecutionThread
        this.threadExecutor = threadExecutor
    }

    protected abstract fun buildUseCaseObservable(): Observable<Any>

    public fun execute(useCaseSubsriber: Subscriber<Any>) {
        subscription = buildUseCaseObservable()
                .subscribeOn(Schedulers.from(threadExecutor))
                .observeOn(postExecutionThread.getScheduler())
                .subscribe(useCaseSubsriber)
    }

    public fun unsubsribe() {
        if (!subscription.isUnsubscribed())
            subscription.unsubscribe()
    }
}
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履行

Inject
class GetDrawerListUseCase(threadExecutor: ThreadExecutor, 
postExecutionThread:PostExecutionThread) : UseCase(threadExecutor, …
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generics android reactive-programming kotlin rx-java

1
推荐指数
1
解决办法
2466
查看次数

在verilog中实现PIPO

我期待在verilog HDL中实现32位并行并行输出.这是我写的代码......

module pipo(input_seq, answer,reset, clock);
   input [31:0] input_seq;
   input        reset,clock;
   output [31:0] answer;

   always @ (reset)
     begin
        if(!reset)
          begin
             answer[31:0]<=1'b0;
          end
     end

   always @ (posedge clock)
     begin
        answer[31:1]<=input_seq[30:0];  
     end

endmodule
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但是,这会导致以下错误日志(使用iverilog):

pipo.v:10: error: answer['sd31:'sd0] is not a valid l-value in pipo.
pipo.v:4:      : answer['sd31:'sd0] is declared here as wire.
pipo.v:16: error: answer['sd31:'sd1] is not a valid l-value in pipo.
pipo.v:4:      : answer['sd31:'sd1] is declared here as wire.
Elaboration failed
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有什么问题?

verilog icarus

0
推荐指数
1
解决办法
1187
查看次数