不知何故,EF在两个查询之间处理ObjectContext,没有任何进一步的通知,但显然不是随机的,也不是由于超时.
我添加了使用,所以示例是自包含的,但它与整个应用程序中使用的DbContext相同.
using (MyDbContext db = new MyDbContext ())
{
//I am sure these are unique
Employee emp = db.Employees.Single(e => e.FirstName == "Bob" && e.LastName == "Morane");
Node node = db.Nodes.Single(n => n.ShortName == "stuff"); //Here the request throws
// "ObjectContext instance has been disposed and can no longer be used for operations that require a connection"
}
Run Code Online (Sandbox Code Playgroud)
通知db尚未使用,因此这是不可能的.错误也发生在.First()和.Where().Single/First().
反转这两个请求不起作用:
using (MyDbContext db = new MyDbContext ())
{
Node node = db.Nodes.Single(n => …Run Code Online (Sandbox Code Playgroud) 嗨,我必须为系统调用编写2个函数,这些函数将管理操作系统中的任务执行.我找不到暂停/重启进程的方法.我找到了一个信号列表,我知道kill函数,这里是我的代码:
#include <stdlib.h>
#include <signal.h>
typedef struct File
{
int pid;
struct File *pids;
} *file;
file file1 = NULL;
//this fonction is to suspend a process using its pid number
int V(int pid_num)
{
//does the kill fonction just kill the process or will it take into account the signal argument?
kill(pid_num, SIGSTOP);
file1 = ajouter(file1, pid_num);
return 0;
}
//this is to restart the process
int C()
{
if (file1 != NULL)
{
//I know the kill fonction …Run Code Online (Sandbox Code Playgroud) 使用过这个程序,如何计算回溯算法的时间复杂度?
/*
Function to print permutations of string This function takes three parameters:
1. String
2. Starting index of the string
3. Ending index of the string.
*/
void swap (char *x, char *y)
{
char temp;
temp = *x;
*x = *y;
*y = temp;
}
void permute(char *a, int i, int n)
{
int j;
if (i == n)
printf("%s\n", a);
else
{
for (j = i; j <= n; j++)
{
swap((a+i), (a+j));
permute(a, i+1, n);
swap((a+i), …Run Code Online (Sandbox Code Playgroud) 我有2个帖子.我的目标是第一个终止自己的执行,必须停止另一个线程.可能吗?
我有这个代码:
#include <stdio.h>
#include <pthread.h>
#include <sys/types.h>
void* start1(void* arg)
{
printf("I'm just born 1\n");
int i = 0;
for (i = 0;i < 100;i++)
{
printf("Thread 1\n");
}
printf("I'm dead 1\n");
pthread_exit(0);
}
void* start2(void* arg)
{
printf("I'm just born 2\n");
int i = 0;
for (i = 0;i < 1000;i++)
{
printf("Thread 2\n");
}
printf("I'm dead 2\n");
pthread_exit(0);
}
void* function()
{
int k = 0;
int i = 0;
for (i = 0;i < 50;i++)
{ …Run Code Online (Sandbox Code Playgroud)