我有两个清单
first= (1,2,3,4,5,6)
last=(6,5,4,3,2,1)
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我只需要比较相应的值。我使用了下面的代码并获得了 36 个结果,因为第一个元素与最后一个列表的所有六个元素进行比较。
for x in first:
for y in last:
if x>y:
print("first is greater then L2",y)
elif x==y:
print("equal")
else:
print("first is less then L2",y)
irst= (1,2,3,4,5,6)
last=(6,5,4,3,2,1)
for x in first:
for y in last:
if x>y:
print("first is greater then L2",y)
elif x==y:
print("equal")
else:
print("first is less then L2",y)
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输出:
L1 is less then L2 6
L1 is less then L2 5
L1 is less then L2 4
L1 is less …Run Code Online (Sandbox Code Playgroud)