小编Pra*_*ash的帖子

我正在前端工作，需要在单击按钮时将手形光标更改为忙碌光标。但我的代码抛出“类型错误”。我只想让代码显示一个按钮，单击该按钮会从手形光标更改为繁忙光标，然后返回正常光标。

这是我迄今为止尝试过的代码：

import threading
from threading import Thread
from threading import Event
import queue

sem=threading.Semaphore()

def setup_for_long_running_task(self):
    print("start")
    self.f1.config(cursor="wait")  # Set the cursor to busy
    sem.acquire()

    return_que = queue.Queue(1)
    workThread = Thread(target=lambda q, w_self: \
                        q.put(self.long_running_task()),
                        args=return_que)
    workThread.start()

    self.f1.after(5000,use_results_of_long_running_task(self,workThread,return_que))  # 500ms is half a second
    sem.release()
    print("stop")

def long_running_task(self):

    Event().wait(3.0)  # Simulate long running task

def use_results_of_long_running_task(self, workThread,return_que):
    ThreadRunning = 1
    while ThreadRunning:
        Event().wait(0.1)  # this is set to .1 seconds. Adjust for your process
        ThreadRunning = workThread.is_alive()

    while not …