小编Hao*_*ang的帖子

两个线程需要按此顺序打印-

Thread1:0    
Thread2:::0    
Thread1:1    
Thread2:::1    
Thread1:2    
Thread2:::2    
Thread1:3    
Thread2:::3
Thread1:::4    
Thread2:::4    
.    
.    
.   
Thread1:100    
Thread2:::100
...

目前这是我的代码，不知何故它卡住了。. 不知道为什么它没有按预期运行

public class Solution{
    private volatile boolean isOneTurn;

    public Solution(){
        isOneTurn = true;
    }

    public void test(){
        Thread t1 = new Thread(new MyThread1("Thread1"));
        Thread t2 = new Thread(new MyThread2("Thread2"));

        t1.start();
        t2.start();
    }

    class MyThread1 implements Runnable {
        public String name;

        public MyThread1(String name) {
            this.name = name;
        }
        @SneakyThrows
        @Override
        public void run() {
            for (int i = 1; i <= 100; …