我想通过以下代码在 lambda 处理程序之外调用异步函数:
var client;
(async () => {
var result = await initSecrets("MyWebApi");
var secret = JSON.parse(result.Payload);
client= new MyWebApiClient(secret.API_KEY, secret.API_SECRET);
});
async function initSecrets(secretName) {
var input = {
"secretName" : secretName
};
var result = await lambda.invoke({
FunctionName: 'getSecrets',
InvocationType: "RequestResponse",
Payload: JSON.stringify(input)
}).promise();
return result;
}
exports.handler = async function (event, context) {
var myReq = await client('Request');
console.log(myReq);
};
Run Code Online (Sandbox Code Playgroud)
“客户端”未初始化。如果在处理程序中执行,相同的代码可以完美运行。initSecrets 包含 getSecrets() 的 lambda 调用,它调用 AWS SecretsManager 有谁知道如何在处理程序外部正确调用异步函数以进行初始化?
非常感谢您的支持。
asynchronous initialization async-await aws-lambda aws-secrets-manager
如何在异步函数中创建 AWS S3 对象的读取流?
如果我尝试
exports.handler = async (event) => {
var csvreadstream = await s3.getObject({ Bucket: bucket, Key: filename }).promise().createReadStream()
}
Run Code Online (Sandbox Code Playgroud)
或者
exports.handler = async (event) => {
var s3Object = await s3.getObject({ Bucket: bucket, Key: filename }).promise();
var csvreadstream = s3Object.createReadStream();
}
Run Code Online (Sandbox Code Playgroud)
我明白了
{
"errorType": "TypeError",
"errorMessage": "(intermediate value).createReadStream is not a function",
"trace": [
"TypeError: (intermediate value).createReadStream is not a function",
" at Runtime.exports.handler (/var/task/app.js:29:86)",
" at processTicksAndRejections (internal/process/task_queues.js:94:5)"
]
}
Run Code Online (Sandbox Code Playgroud)
谁能建议如何以异步(异步/等待方式)函数从 S3 对象创建读取流?谢谢你!
感谢 Mark BI,我又向前迈进了一步: …
amazon-s3 amazon-web-services node.js async-await aws-lambda