小编Pet*_*zov的帖子

我使用默认的JavaFX选项卡窗格布局

我想在旧的标签下方显示新标签.我不想显示默认上下文菜单来选择要显示的选项卡.有没有改变这个的选择？

我注意到当我在JVM 7和JVM 8上运行JavaFX应用程序时,我获得了不同的默认外观.如何在每个JVM上将默认外观设置为相同？

我测试了使用Netbeans 7.4创建JavaFX 8项目.但遗憾的是没有运气.这是POM文件:

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>

    <groupId>com.dx57dc</groupId>
    <artifactId>JFX8M</artifactId>
    <version>1.0</version>
    <packaging>jar</packaging>

    <name>JFX8M</name>

    <properties>
        <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
        <mainClass>com.dx57dc.jfx8m.MainApp</mainClass>
    </properties>

    <build>
        <plugins>
            <plugin>
                <groupId>org.apache.maven.plugins</groupId>
                <artifactId>maven-dependency-plugin</artifactId>
                <version>2.8</version>
                <executions>
                    <execution>
                        <id>unpack-dependencies</id>
                        <phase>package</phase>
                        <goals>
                            <goal>unpack-dependencies</goal>
                        </goals>
                        <configuration>
                            <excludeScope>system</excludeScope>
                            <excludeGroupIds>junit,org.mockito,org.hamcrest</excludeGroupIds>
                            <outputDirectory>${project.build.directory}/classes</outputDirectory>
                        </configuration>
                    </execution>
                </executions>
            </plugin>
            <plugin>
                <groupId>org.codehaus.mojo</groupId>
                <artifactId>exec-maven-plugin</artifactId>
                <version>1.2.1</version>
                <executions>
                    <execution>
                        <id>unpack-dependencies</id>

                        <phase>package</phase>
                        <goals>
                            <goal>exec</goal>
                        </goals>
                        <configuration>
                            <executable>${java.home}/../bin/javafxpackager</executable>
                            <arguments>
                                <argument>-createjar</argument>
                                <argument>-nocss2bin</argument>
                                <argument>-appclass</argument>
                                <argument>${mainClass}</argument>
                                <argument>-srcdir</argument>
                                <argument>${project.build.directory}/classes</argument>
                                <argument>-outdir</argument>
                                <argument>${project.build.directory}</argument>
                                <argument>-outfile</argument>
                                <argument>${project.build.finalName}.jar</argument>
                            </arguments>
                        </configuration>
                    </execution>
                </executions>  
            </plugin>
            <plugin>
                <groupId>org.apache.maven.plugins</groupId>
                <artifactId>maven-compiler-plugin</artifactId>
                <version>3.1</version>
                <configuration>
                    <source>1.8</source>
                    <target>1.8</target>
                    <compilerArguments>
                        <bootclasspath>${sun.boot.class.path}${path.separator}${java.home}/lib/jfxrt.jar</bootclasspath> …

有没有办法将Java应用程序编码为仅使用CPU的2个CPU内核.例如,我想设置CPU利用率的限制.这在Java中可行吗？

我想将java arraylist显示到JSF页面中.我从数据库生成了arraylist.现在我想通过索引号调用列表元素索引将列表显示到JSF页面.是否可以直接从JSF页面中的EL表达式向bean方法传递参数并显示它？

实时更新折线图

我想修改这个简单的折线图示例并添加实时更新.

import javafx.application.Application;
import javafx.scene.Scene;
import javafx.scene.chart.LineChart;
import javafx.scene.chart.NumberAxis;
import javafx.scene.chart.XYChart;
import javafx.stage.Stage;


public class LineChartSample extends Application {

    @Override public void start(Stage stage) {
        stage.setTitle("Line Chart Sample");
        //defining the axes
        final NumberAxis xAxis = new NumberAxis();
        final NumberAxis yAxis = new NumberAxis();
        xAxis.setLabel("Number of Month");
        //creating the chart
        final LineChart<Number,Number> lineChart = 
                new LineChart<Number,Number>(xAxis,yAxis);

        lineChart.setTitle("Stock Monitoring, 2010");
        //defining a series
        XYChart.Series series = new XYChart.Series();
        series.setName("My portfolio");
        //populating the series with data
        series.getData().add(new XYChart.Data(1, 23));
        series.getData().add(new XYChart.Data(2, 14)); …

我在显示套接字的/ proc中找到此信息：

$ cat /proc/net/sockstat 
sockets: used 8278
TCP: inuse 1090 orphan 2 tw 18 alloc 1380 mem 851
UDP: inuse 6574
RAW: inuse 1
FRAG: inuse 0 memory 0

您能帮我找出这些值的含义吗？这些值是否足够可靠，还是我需要在其他地方搜索？

这些其他方法可以找到有关Linux中TCP / UDP连接的信息吗？

我想将 TIMESTAMP 插入 LAST_LOGIN 列

CREATE TABLE USER(
 ID INTEGER NOT NULL,
 USER_NAME TEXT,
 FIRST_NAME TEXT,
 LAST_NAME TEXT,
 LAST_LOGIN DATE,
 DATE_REGISTERED DATE,
 ROLE INTEGER,
 CAN_LOGIN INTEGER
)
;

ALTER TABLE USER ADD CONSTRAINT KEY1 PRIMARY KEY (ID)
;

我试过这个：

UPDATE USERS SET LAST_LOGIN = TIMESTAMP WHERE USER_NAME = ?

但我得到 org.postgresql.util.PSQLException: ERROR: column "timestamp" does not exist Position: 31

将当前时间插入表列 LAST_LOGIN 的正确方法是什么？

我想为JSF表添加过滤器,并根据过滤器值限制值.

<h:inputText id="search" value="#{accounts.searchString}"></h:inputText>

<h:commandButton value="Search" action="#{accounts.search()}">
    <f:ajax execute="search" render="output"></f:ajax>
</h:commandButton>

我想最好的方法是将过滤器值添加到SQL查询中:

SELECT * FROM CUSTOMERS ORDER BY %S %S offset ? limit ?

完整代码:http://pastebin.com/eEeTWEqK

我如何将代码实现为链接？

PS.我这样修改了代码:

<div class="div_input_style">
    <h:inputText id="search" class="input_style" value="#{accounts.searchString}"></h:inputText>

    <h:commandButton class="theSpan" value="Search by title">
        <f:ajax execute="search" render="output"></f:ajax>
    </h:commandButton>
</div>

public List<AccountsObj> list(int firstRow, int rowCount, String sortField, boolean sortAscending) throws SQLException
    {
        String SqlStatement = null;

        if (ds == null)
        {
            throw new SQLException();
        }

        Connection conn = ds.getConnection();
        if (conn == null) …

我有这个JPA查询,我想从Spring生成Angular Barchart:

    public List<PaymentTransactionsDailyFacts> findPaymentTransactionsDailyFacts(LocalDateTime start_date, LocalDateTime end_date) {

        String hql = "SELECT SUM(amount) AS sum_volume, COUNT(*) AS sum_Transactions " + 
                " WHERE (created_at BETWEEN :start_date AND :end_date )" + 
                " GROUP BY DATE(created_at)";

        TypedQuery<PaymentTransactionsDailyFacts> query = entityManager.createQuery(hql,
                PaymentTransactionsDailyFacts.class).setParameter("start_date", start_date).setParameter("end_date", end_date);
        List<PaymentTransactionsDailyFacts> data = query.getResultList();
        return data;
    }

预期的查询结果:

Date       | Amount| Number of transactions per day |
11-11-2018 | 30    | 3                              |
11-12-2018 | 230   | 13                             |

JPA查询中的映射对象:

public class DashboardDTO {

    private Date date;

    private int …