小编Pet*_*zov的帖子

类型“ Observable <Blob>”上不存在属性“ map”

我想使用此Angular 6代码实现文件下载:

REST API:

@GetMapping("export")
    public ResponseEntity<InputStreamResource> export() throws IOException {
        ClassPathResource pdfFile = new ClassPathResource(EXTERNAL_FILE_PATH);

        HttpHeaders headers = new HttpHeaders();
        headers.add("Cache-Control", "no-cache, no-store, must-revalidate");
        headers.add("Pragma", "no-cache");
        headers.add("Expires", "0");

        return ResponseEntity.ok().headers(headers).contentLength(pdfFile.contentLength())
                .contentType(MediaType.parseMediaType("application/pdf"))
                .body(new InputStreamResource(pdfFile.getInputStream()));
    }
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服务:

import {Injectable} from '@angular/core';
import {HttpClient, HttpParams} from "@angular/common/http";
import {Observable} from "rxjs/index";
import {environment} from "../../../environments/environment";
import {HttpUtils} from "../common/http-utils";
import { map } from 'rxjs/operators';

@Injectable({
  providedIn: 'root'
})
export class DownloadService {

  constructor(private http: HttpClient) {
  }

  downloadPDF(): any {
    return …
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typescript angular angular6 angular7

-1
推荐指数
1
解决办法
1135
查看次数

模拟服务不使用带有 Autowire 的构造函数但使用 Java 方法

我想编辑此代码以使用模拟服务。这段代码工作正常:

@Service
public class BinCountryCheckFilterImpl {

    private RiskFilterService riskFilterService;
    private Terminals terminal;

    @Autowired
    public BinCountryCheckFilterImpl(Terminals terminal, RiskFilterService riskFilterService) {  
        this.terminal = terminal;
        this.riskFilterService = riskFilterService;
    }

    public void validateBinCountryCheckFilter(Terminals terminal) throws JAXBException, JsonProcessingException {

        List<RiskFilters> filter_list = riskFilterService.findRiskFiltersByTerminalIdAndType(terminal.getId(), "BinCountryCheckFilter");
    }
}
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JUnit 测试:

public class BinCountryCheckFilterImplTest    {

    @Test
    public void testBinCountryCheckFilterImpl() throws JsonProcessingException, JAXBException {
        //Arrange
        RiskFilterService riskFilterService = Mockito.mock(RiskFilterService.class);
        Terminals terminal = Mockito.mock(Terminals.class);

        BDDMockito.given(
            riskFilterService.findRiskFiltersByTerminalIdAndType(anyInt(), anyString()))
            .willReturn(riskFiltersList);

        int expectedInt = 11;
        String expectedString = "BinCountryCheckFilter";

        when(terminal.getId()).thenReturn(expectedInt);

        BinCountryCheckFilterImpl binCountryCheckFilterImpl = …
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java junit spring spring-boot junit5

-1
推荐指数
1
解决办法
269
查看次数

使用提示优化 Oracle 查询

我有一个复杂的 Oracle 查询。

SELECT
    r3.object_id
FROM
    nc_references r
    INNER JOIN nc_objects     o ON r.object_id = o.object_id
                               AND o.object_class_id = 90000330 /* Work Item */
    INNER JOIN nc_params      p ON p.object_id = o.object_id
                              AND p.attr_id = 90100070 /* State */  AND p.list_value_id IN ( 90100071 /* Ready */, 90100072 /* Active */ )
    INNER JOIN nc_po_actions  poa ON poa.manual_task_id = o.object_id
    INNER JOIN nc_po_tasks    pot ON pot.task_id = poa.task_id
    INNER JOIN nc_references  r1 ON r1.object_id = pot.container_id
                                   AND r1.attr_id = 9145923960313063683 …
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sql oracle query-hints oracle11g

-1
推荐指数
1
解决办法
862
查看次数

不支持的参数值:“YEARS”

我想运行这段代码:

final LocalTime currentTime = LocalTime.now().plus(2, ChronoUnit.YEARS);
long milliseconds = currentTime.toNanoOfDay() / 1000000;
String s = Long.toHexString(milliseconds).toUpperCase();
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我收到错误:

Unsupported argument value: 'YEARS'你知道我该如何解决这个问题吗?

java java-time

-1
推荐指数
1
解决办法
110
查看次数

如何插入日期

我写了一个用于插入当前日期的java代码,但是当我尝试运行它时会发生异常:

public void Session_Table_Update (String Update_User) throws SQLException{
           String  SQL_Statement = null;
           error_Message = null;
            if (ds == null) throw new SQLException( error_Database = "No data source");      
       Connection conn = ds.getConnection();
            if (conn == null) throw new SQLException( error_Database = "No connection");      

       try {
            conn.setAutoCommit(false);
            boolean committed = false;
                try {
                    SQL_Statement = "INSERT INTO USERS (LAST_LOGIN) VALUES (?,?,?) WHERE USERZ ="+ Update_User;

                       PreparedStatement insertQuery = conn.prepareStatement(SQL_Statement);
                       insertQuery.setString(3, "2.2.2011");

                       insertQuery.executeUpdate();                  


                       conn.commit();
                       committed = true;
                 } finally {
                       if (!committed) conn.rollback(); …
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java date jdbc

-2
推荐指数
1
解决办法
693
查看次数

SQL - 如何使用一个SQL语句更新两个行表

我有这个Oracle表,用于存储应用程序设置.

在此输入图像描述

这是用于创建表的SQL脚本:

CREATE TABLE "GLOBALSETTINGS"(
  "SettingName" Varchar2(40 ) NOT NULL,
  "SettingValue" Varchar2(40 )
)
/

-- Add keys for table GLOBALSETTINGS

ALTER TABLE "GLOBALSETTINGS" ADD CONSTRAINT "Key14" PRIMARY KEY ("SettingName")
/

ALTER TABLE "GLOBALSETTINGS" ADD CONSTRAINT "SettingName" UNIQUE ("SettingName")
/
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这是我想要使用的SQL语句:

UPDATE GLOBALSETTINGS
SET settingValue =
  CASE
    WHEN settingName = 'SessionTTL'
    THEN '30'
    WHEN settingName = 'MaxUsersActive'
    THEN '40'
    ELSE settingValue
  END
WHERE settingName IN ('SessionTTL', 'MaxUsersActive');
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但是当我在SQL开发人员中运行它时,我收到以下错误消息:

Error starting at line 1 in command:
UPDATE GLOBALSETTINGS 
   SET settingValue = …
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sql oracle oracle10g oracle11g

-2
推荐指数
1
解决办法
1216
查看次数

找不到进入JSF页面的bug

我正在尝试实现本教程中的代码:

这是托管bean:

import java.io.Serializable;
import javax.enterprise.context.SessionScoped;
// or import javax.faces.bean.SessionScoped;
import javax.inject.Named;
/* include SQL Packages */
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.util.ArrayList;
import java.util.Date;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import javax.annotation.PostConstruct;
import javax.sql.DataSource;
import javax.annotation.Resource;
import javax.faces.bean.ViewScoped;
import javax.faces.component.UICommand;
import javax.faces.context.FacesContext;
import javax.inject.Inject;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpSession;
// or import javax.faces.bean.ManagedBean; 
import javax.faces.event.ActionEvent;

import org.glassfish.osgicdi.OSGiService;

// source http://balusc.blogspot.com/2008/10/effective-datatable-paging-and-sorting.html
@Named("SessionsController")
@ViewScoped
public class Sessions implements Serializable {

    /* Call the Oracle JDBC Connection driver */ …
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java jsf jsf-2

-2
推荐指数
1
解决办法
267
查看次数

如何将元素排序到C++矩阵中?

我是C++编程的新手.我需要对这个矩阵进行排序:

#include <iostream>
#include <iomanip>


#include <cstdlib>

using namespace std;


int main(int argc, char** argv) {

    Mat10 a;
    fillRand(a, 5, 5);
    prnMat(a, 5, 5);
    cout << endl;

    return 0;
}

void fillRand(Mat10 m, int n, int k) {
    for (int i = 0; i < n; i++)      
        for (int j = 0; j < k; j++)
            m[i][j] = rand() % 1000;    
}

void prnMat(Mat10 a, int m, int n) {
    for (int i = 0; i < m; i++) { …
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c++

-3
推荐指数
2
解决办法
7873
查看次数

使用键和值将HashMap转换为String

我想创建一个util方法,它使用键和值将HashMap转换为long String:

HashMap<String, String> map = new LinkedhashMap<>();

map.put("first_key", "first_value");
map.put("second_key", "second_value");
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我需要得到这个最终结果:

first_key=first_value&second_key=second_value
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java string hashmap

-3
推荐指数
1
解决办法
2048
查看次数

创建50 MB Java对象

如何创建固定大小为50 MB的Java对象?

我需要此Object用于数据库测试,以便在插入大对象时测量表空间名称.

java

-4
推荐指数
1
解决办法
561
查看次数

从兰特得到数字

我怎么能从间隔之间的Ruby rand方法得到总数rand(1..99999999).

例如,我希望得到例如1000或100000的结果

ruby

-4
推荐指数
1
解决办法
77
查看次数

将字符串转换为列表

我有用于转换为字符串的列表:

    private String convertList(List<String> list)
    {
        String listString = "";

        for (String s : list)
        {
            listString += s + ",";
        }
        return listString;
    }
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但我也想向后实现相同的操作。我想使用,作为分隔符的字符串生成列表。如何实施?

java

-5
推荐指数
1
解决办法
2万
查看次数