小编Sam*_*son的帖子

考虑：

def foobar(*, foo, bar):
    if foo:
        print('foo', end="")
    if bar:
        print('bar', end="")
    if foo and bar:
        print('No bueno', end='')  # I want this to be impossible
    if not foo and not bar:
        print('No bueno', end='')  # I want this to be impossible
    print('')


foobar(foo='bar')  # I want to pass inspection
foobar(bar='foo')  # I want to pass inspection
foobar(foo='bar', bar='foo')  # I want to fail inspection
foobar()  # I want to fail inspection

有没有一种方法可以设置一个函数，使调用它的方法仅在仅传递foo或bar时才通过检查，而无需手动检查函数内部？