我想使用 OpenCV 的estimateRigidTransform 函数,但它抛出了一个错误。
AttributeError Traceback (most recent call last) in 30 31 #Find transformation matrix ---> 32 m = cv2.estimateRigidTransform(prev_pts, curr_pts, fullAffine=False) #will only work with OpenCV-3 or less 33 34 # Extract traslation
AttributeError: 模块 'cv2.cv2' 没有属性 'estimateRigidTransform'
我的 openCV 版本是 4.0.0。
我试图在布局内设置散景图的绝对位置,以便其中一个图显示在另一个图的顶部。现在当我在绘制这样的东西时:
from bokeh.io import curdoc
from bokeh.plotting import figure
from bokeh.layouts import layout
import numpy as np
x = np.arange(1,10.1,0.1)
y = [i**2 for i in x]
categories = ['A', 'B']
values = [1000, 1500]
fig1 = figure(width=600,plot_height=600, title="First Plot")
fig1.line(x=x, y=y)
fig2 = figure(width=200,plot_height=250,x_range=categories,
title="Second Plot") fig2.vbar(x=categories, top=values, width=0.2)
l = layout([[fig1,fig2]])
curdoc().add_root(l)
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结果将是这样的:
我正在寻找的是某种使它看起来像这样的方法:
怎样才能达到这个结果?
谢谢!
I am studying the price of a product along time. I have daily data with some missing info at random.
See here a minimal example where info for the 4th of January is missing:
library(lubridate)
library(data.table)
mockData <- data.table(timeStamp=c(ymd("20180101"), ymd("20180102"), ymd("20180103"), ymd("20180105")),
price=c(10,15,12,11))
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I want to add the lagged price to my data.table but if the previous day is missing, I want a NA instead of the closest day with info.
I explain myself:
If I use the shift function: …
我正在尝试将文件从 E:/bin/Debug/ 复制到 E:/New 使用xcopy. 我的语法是
xcopy /s "E:\bin\Debug*.*E:\New"
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在 Windows 10 上。
它返回
错误 参数数量无效
或有时
新未找到无效路径
. 请帮我找出我的错误。我究竟做错了什么?