小编joh*_*nuc的帖子

我有一个小问题; 在PHP中,我使用curl从URL获取数据:

$url = "http://www.prelovac.com/vladimir/wp-content/uploads/2008/03/example.jpg";

我用curl_getinfo()它给了我一个数组:

Array
(
[url] => http://www.prelovac.com/vladimir/wp-content/uploads/2008/03/example.jpg
[content_type] => image/jpeg
[http_code] => 200
[header_size] => 496
[request_size] => 300
[filetime] => -1
[ssl_verify_result] => 0
[redirect_count] => 0
[total_time] => 2.735
[namelookup_time] => 0.063
[connect_time] => 0.063
[pretransfer_time] => 0.063
[size_upload] => 0
[size_download] => 34739
[speed_download] => 12701
[speed_upload] => 0
[download_content_length] => 34739
[upload_content_length] => -1
[starttransfer_time] => 1.282
[redirect_time] => 0
)

如何在链接中获取图像的名称,[url] => http://www.prelovac.com/vladimir/wp-content/uploads/2008/03/example.jpg例如

[image_name] : example
[image_ex] …

我正在使用javascript中的图像高度,

我的代码:

<script>
    var  linkBg = 'http://imageshack.us/a/img24/5489/2013042200001.jpg';
    var bgimg = new Image();
        bgimg.src = linkBg;
        var bgHeight = bgimg.height;
        alert(bgHeight);
</script>

我的问题是:当我在Firefox上运行此脚本时,它返回图像的高度,但在Chrome上它返回0.

如何在没有Jquery的情况下仅使用javascript来解决此问题,感谢您的帮助!

我正在处理复制文件,我可以将一个文件复制到多个文件夹,但是在将多个文件复制到多个文件夹时遇到问题.

我的代码:

$sourcefiles = array('./folder1/test.txt', './folder1/test2.txt');

$destinations = array('./folder2/test.txt', './folder2/test2.txt');

//do copy

foreach($sourcefiles as $source) {

    foreach($destinations as $des){
        copy($source, $des);
    }

}

但是这段代码不起作用!

你能给我一个解决方案:(

谢谢你的帮助 !