我想获得在c中添加两个无符号64位整数的进位位。如果需要,我可以使用x86-64 asm。码:
#include <stdio.h>
typedef unsigned long long llu;
int main(void){
llu a = -1, b = -1;
int carry = /*carry of a+b*/;
llu res = a+b;
printf("a+b = %llu (because addition overflowed), carry bit = %d\n", res, carry);
return 0;
}
Run Code Online (Sandbox Code Playgroud) 我在C ++中编写一个512位整数。对于整数,我使用new关键字从堆中分配内存,但是编译器(MINGW上的g ++版本8.1)似乎错误地对其进行了优化。即编译器命令是:
g++ -Wall -fexceptions -Og -g -fopenmp -std=c++14 -c main.cpp -o main.o
g++ -o bin\Debug\cs.exe obj\Debug\main.o -O0 -lgomp
码:
#include <iostream>
#include <cstdint>
#include <omp.h>
constexpr unsigned char arr_size = 16;
constexpr unsigned char arr_size_half = 8;
void exit(int);
struct uint512_t{
uint32_t * bytes;
uint512_t(uint32_t num){
//The line below is either (wrongfully) ignored or (wrongfully) optimized out
bytes = new(std::nothrow) uint32_t[arr_size];
if(!bytes){
std::cerr << "Error - not enough memory available.";
exit(-1);
}
*bytes = num;
for(uint32_t …Run Code Online (Sandbox Code Playgroud)