我有一个包裹在 Task.Run 下的异步 lambda 表达式。但是,看起来我可以删除 async 和 await 关键字,它们会产生相同的结果。
t1 = Task.Run(() => DoSomethingExpensiveAsync());
t2 = Task.Run(() => DoSomethingExpensiveAsync());
await Task.WhenAll(t1, t2);
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对比
var t1 = Task.Run(async () => await DoSomethingExpensiveAsync());
var t2 = Task.Run(async () => await DoSomethingExpensiveAsync());
await Task.WhenAll(t1, t2);
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