我使用client.upload在pkgcloud上传文件的目录.所有流完成后执行回调的最佳方法是什么?是否有一种内置方式来注册每个流的"完成"事件并在它们全部被触发后执行回调?
var filesToUpload = fs.readdirSync("./local_path"); // will make this async
for(let file of filesToUpload) {
var writeStream = client.upload({
container: "mycontainer,
remote: file
});
// seems like i should register finish events with something
writeStream.on("finish", registerThisWithSomething);
fs.createReadStream("./local_path/" + file).pipe(writeStream);
}
Run Code Online (Sandbox Code Playgroud) 如何将python方法/槽连接到QML信号?看起来QtObject.connect()曾经在PyQt4中工作,但它在PyQt5中不再可用.
#Sample QML File (stack.qml)
import QtQuick 2.0
Rectangle {
MouseArea {
anchors.fill: parent
onClicked: {
// relay this to python
}
}
}
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-
#Sample Python File
from PyQt5.QtCore import QUrl
from PyQt5.QtGui import QGuiApplication
from PyQt5.QtQuick import QQuickView
if __name__ == '__main__':
import os
import sys
app = QGuiApplication(sys.argv)
view = QQuickView()
view.setWidth(500)
view.setHeight(500)
view.setTitle('Hello PyQt')
view.setResizeMode(QQuickView.SizeRootObjectToView)
view.setSource(QUrl.fromLocalFile(os.path.join(os.path.dirname(__file__),'stack.qml')))
def on_qml_mouse_clicked(mouse_event):
print 'mouse clicked'
view.show()
qml_rectangle = view.rootObject()
# this technique doesn't work #############################
qml_rectangle.mousePressEvent.connect(on_qml_mouse_clicked)
sys.exit(app.exec_())
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一些PyQT示例通过"setContextProperty"将对象传递到QML上下文,然后将QML事件中继到该对象上的插槽,但这种方法似乎是迂回的.有没有更好的办法?
我对couchDB很新,甚至在阅读之后(最新的存档已删除)http://wiki.apache.org/couchdb/How_to_store_hierarchical_data(通过'存储每个节点的完整路径作为该节点文档中的属性')它还没有点击.
而不是使用维基中描述的完整路径模式,我希望将子项跟踪为UUID数组,父项作为单个UUID.我倾向于这种模式,所以我可以通过他们在儿童阵列中的位置维持孩子的顺序.
以下是沙发中的一些示例文档,存储桶可以包含存储桶和项目,项目只能包含其他项目.(UUID缩写为清晰):
{_id: 3944
name: "top level bucket with two items"
type: "bucket",
parent: null
children: [8989, 4839]
}
{_id: 8989
name: "second level item with no sub items"
type: "item"
parent: 3944
}
{
_id: 4839
name: "second level bucket with one item"
type: "bucket",
parent: 3944
children: [5694]
}
{
_id: 5694
name: "third level item (has one sub item)"
type: "item",
parent: 4839,
children: [5390]
}
{
_id: 5390
name: "fourth level item"
type: …Run Code Online (Sandbox Code Playgroud) 试图弄清楚如何从MonoMac应用程序中显示webkit控制台或检查器.看起来它可以通过设置WebKitDeveloperExtras在Objective-C中完成.
[USER_DEFAULTS registerDefaults:[NSDictionary dictionaryWithObject:
[NSNumber numberWithBool:YES] forKey:@"WebKitDeveloperExtras"]];
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如何在MonoMac.WebKit.WebView中设置WebDeveloperExtras?