小编Ron*_*sen的帖子

我目前在Symfony2 2.3.7上.当我运行composer update命令时.在post-update-cmd中,运行脚本以更新symfony2.但它失败了:

Script Sensio\Bundle\DistributionBundle\Composer\ScriptHandler::buildBootstrap handling the post-update-cmd event terminated with an exception

  [RuntimeException]                                     
  An error occurred when generating the bootstrap file.  

update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-plugins] [--no-custom-installers] [--no-scripts] [--no-progress] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [packages1] ... [packagesN]

知道为什么会这样吗？我试着跑:

composer update --no-scripts 

..而且运行正常.以下工作正常:

php vendor/sensio/distribution-bundle/Sensio/Bundle/DistributionBundle/Resources/bin/build_bootstrap.php

但每次我尝试正常的作曲家更新时,帖子脚本都会失败.使用--verbose运行更新提供以下内容:

Script Sensio\Bundle\DistributionBundle\Composer\ScriptHandler::buildBootstrap handling the post-update-cmd event terminated with an exception

  [RuntimeException]                                     
  An error occurred when generating the bootstrap file.                                                      

Exception trace:
 () at C:\xampp\htdocs\forvaltning\vendor\sensio\distribution-bundle\Sensio\Bundle\DistributionBundle\Composer\ScriptHandler.php:203
 Sensio\Bundle\DistributionBundle\Composer\ScriptHandler::executeBuildBootstrap() at C:\xampp\htdocs\forvaltning\vendor\sensio\distribution-bundle\Sensio\Bundle\DistributionBundle\Composer\ScriptHandler.php:43
 Sensio\Bundle\DistributionBundle\Composer\ScriptHandler::buildBootstrap() at phar://C:/ProgramData/Composer/bin/composer.phar/src/Composer/EventDispatcher/EventDispatcher.php:165
 Composer\EventDispatcher\EventDispatcher->executeEventPhpScript() at phar://C:/ProgramData/Composer/bin/composer.phar/src/Composer/EventDispatcher/EventDispatcher.php:138 …

所以我有这个菜单.

<div class="menu">
<ul>
<li class="page_item page-item-23 current_page_item">
<a href="http://localhost/irises/">Forside</a></li>
<li class="page_item page-item-26">
<a href="http://localhost/irises/?page_id=26">Produkter</a>
<ul class='children'>
<li class="page_item page-item-83">
<a href="http://localhost/irises/?page_id=83">Produkt 1</a>
</li>
<li class="page_item page-item-203">
<a href="http://localhost/irises/?page_id=203">Produkt 2</a>
</li>
</ul>
</li>
<li class="page_item page-item-41">
<a href="http://localhost/irises/?page_id=41">Kursuskalender</a>
</li>
<li class="page_item page-item-2">
<a href="http://localhost/irises/?page_id=2">Nyheder</a>
</li>
<li class="page_item page-item-16"><a href="http://localhost/irises/?page_id=16">IRIS Enterprise Solutions</a></li>
<li class="page_item page-item-62">
<a href="http://localhost/irises/?page_id=62">Kontakt</a>
</li>
</ul>
</div>

所以当我这样做的时候

$('.menu ul li').after('<li class="delimiter">|</li>');

我在每个主菜单点之后得到一个分隔符,但也在子菜单中.

<ul class='children'>

如果我只想在主菜单点之间使用这个分隔符,jquery将如何呢？