小编eth*_*ish的帖子

来自 Google Cloud Functions 的 403 响应

尝试从 Web 执行 Cloud Function 端点时,我收到以下错误:

<!DOCTYPE html>
<html lang=en>
  <meta charset=utf-8>
  <meta name=viewport content="initial-scale=1, minimum-scale=1, width=device-width">
  <title>Error 403 (Forbidden)!!1</title>
  <style>
    *{margin:0;padding:0}html,code{font:15px/22px arial,sans-serif}html{background:#fff;color:#222;padding:15px}body{margin:7% auto 0;max-width:390px;min-height:180px;padding:30px 0 15px}* > body{background:url(//www.google.com/images/errors/robot.png) 100% 5pxno-repeat;padding-right:205px}p{margin:11px 0 22px;overflow:hidden}ins{color:#777;text-decoration:none}a img{border:0}@media screen and (max-width:772px){body{background:none;margin-top:0;max-width:none;padding-right:0}}#logo{background:url(//www.google.com/images/branding/googlelogo/1x/googlelogo_color_150x54dp.png) no-repeat;margin-left:-5px}@media only screen and (min-resolution:192dpi){#logo{background:url(//www.google.com/images/branding/googlelogo/2x/googlelogo_color_150x54dp.png) no-repeat 0% 0%/100% 100%;-moz-border-image:url(//www.google.com/images/branding/googlelogo/2x/googlelogo_color_150x54dp.png) 0}}@media only screen and (-webkit-min-device-pixel-ratio:2){#logo{background:url(//www.google.com/images/branding/googlelogo/2x/googlelogo_color_150x54dp.png) no-repeat;-webkit-background-size:100% 100%}}#logo{display:inline-block;height:54px;width:150px}
  </style>
  <a href=//www.google.com/><span id=logo aria-label=Google></span></a>
  <p><b>403.</b> <ins>That’s an error.</ins>
  <p>Access is forbidden.  <ins>That’s all we know.</ins>
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我跟着这个教程:https : //github.com/GoogleCloudPlatform/python-docs-samples/blob/master/functions/helloworld/main.py

调用此处所述的函数时:https : //cloud.google.com/functions/docs/writing/http,我收到 403 错误。我已登录 …

google-cloud-platform google-cloud-functions

19
推荐指数
2
解决办法
1万
查看次数

Python中的嵌套Defaultdicts

我在嵌套的defaultdict中更新列表时遇到问题.

这是我的代码:

a = ['20160115',    'shadyside medical building',   1, 'Review']
b = ['20160115',    'shadyside medical building',   1, 'Video']
c = ['20160215',    'shadyside medical building',   1, 'Video']
d = ['20160215',    'medical building',             1, 'Video']
f = [a,b,c,d]

nested_dict = defaultdict(dict)

for date,keyword,pos,feature in f:
    nested_dict[keyword].update({feature : [pos]})
    nested_dict[keyword].update({feature : [pos]})
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这是输出:

{'shadyside medical building': 
                             {'Review': [1], 
                             'Video': [1]}, 
'medical building': 
                   {'Video': [1]}}
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所需的输出是:

{'shadyside medical building': 
                             {'Review': [1], 
                             'Video': [1,1]}, 
'medical building': 
                   {'Video': [1]}}
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请注意,视频的第二项已添加到视频列表中.

python dictionary defaultdict

3
推荐指数
1
解决办法
1231
查看次数