不幸的是,我正在努力遵循以下计划:
我用一个用户名作为键和关键字"Instagram粉丝"作为其值来搜索一本大字典.
看起来像这样:
dict = {
"User1": ['Follower_A', 'Follower_B', 'Follower_C', 'Follower_D', 'Follower_E', 'Follower_F', 'Follower_G'],
"User2": ['Follower_Z', 'Follower_D', 'Follower_V', 'Follower_E' 'Follower_O'],
"User3": ['Follower_P', 'Follower_Q'],
"User4": ['Follower_M', 'Follower_A', 'Follower_Z', 'Follower_P' 'Follower_L'],
.
.
.,
"UserX": ['Follower_Z', 'Follower_D', 'Follower_V', 'Follower_E' 'Follower_O','Follower_Q']}
为了创建一个网络,我需要有一个如下所示的数据框:
User Follower
0 User1 Follower_A
1 User1 Follower_B
2 User1 Follower_C
3 User1 Follower_D
4 User1 Follower_E
5 User1 Follower_F
6 User1 Follower_G
7 User2 Follower_Z
8 User2 Follower_D
9 User2 Follower_V
10 User2 Follower_E
11 User2 Follower_O
12 User3 Follower_P …