小编F. *_*iot的帖子

I have created a 'dynamic' list of parameters which I pass to parametrize.

OPTIONS = ['a', 'b', 'c']

def get_unique_pairs():
    unique_list = []
    for first in OPTIONS:
        for second OPTIONS:
            if first == second:
                continue
            unique_list.append({'first':first, 'second':second))
    return unique_list

def some_func()
    unique_pairs = get_unique_pairs()
    result = []
    for pair in unique_pair:
        if test(pair):
           continue
        else:
           result.append(pair)
    return pair

@pytest.mark.parametrize('param', some_fnc())
def test_fnc(param):
    first = param['first']
    second = param['second']

The input I wish to pass to test_fnc is [('a','b'),('a','c')...('c','b')] where the …

我有一个函数和一个测试

def foo(a):
    return bar(a)

@pytest.mark.parametrize(
  'number',
    [1,2,3]
)
@pytest.mark.dependency
def test_foo(number):
    assert foo(number) > SOME_CONST # Simplistic example, real case is more nuanced

我正在使用 pytest 和 pytest_dependency 模块。foo是许多其他测试中使用的函数。我有一个函数，我想依赖它test_foo，下面的代码不起作用：

@pytest.mark.dependency(depends=['test_foo'])
@pytest.mark.parametrize(
    'param',
    itertools.permutations(['a','b','c','d','e'],2),
    ids=repr,
)

def test_bar(param):
    ...
    important_result = foo(param)
    ...

理论上来说，如果test_foo失败，那么test_bar就会被跳过。但是，当我参数化 时，无论 的结果如何，都会跳过 的test_bar每个实例化。test_bartest_foo

澄清一下，此代码按预期工作（未跳过 test_bar）：

@pytest.mark.dependency(depends=['test_foo'])
def test_bar():
    param = some_fnc(['a', 'b'])
    ...
    important_result = foo(param)
    ...