所以我试图找到一个列表的所有子列表，这就是我现在所拥有的。我是 Python 新手，我不明白为什么“Q3_ans=set(ans)”会引发错误。我已经尝试将列表转换为之前设置的并且它有效。
def f2(seq):
'''
This is the base case of the recursion from function all_sublists
'''
assert len(seq)==2
assert isinstance(x,list)
a,b=seq
return [[a],[b],[a,b]]
def all_sublists(x):
'''
This function will generate all of the sublists of a list, not including the empty one, using recursion
'''
assert isinstance(x,list)
ans=[]
for i in range(0,len(x)-1):
for j in range(1,len(x)):
temp=[x[i],x[j]]
temp=[f2(temp)]
ans.extend(temp)
Q3_ans=set(ans)
return Q3_ans
这是我运行代码时的错误 y=[1,2,3,4,5]
all_sublists(y)
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-108-f8b1bb0a7001> in <module>
----> 1 all_sublists(y) …