glob.glob(file_naming)
这样做给了我两个文件:
['/srv/tmp/what/123_aaa_bbb_20190110043711.XML',
'/srv/tmp/what/234_xxx_yyy_20190110043710.XML']
如何按最后一部分(20190110043711)的顺序对它们进行排序？我需要一个结果:
['/srv/tmp/what/123_aaa_bbb_20190110043710.XML',
'/srv/tmp/what/234_xxx_yyy_20190110043711.XML']