小编Raf*_*ski的帖子

我想打印一个很长的数字的所有位.当我在main()中执行它时一切都很好,但在printBits()函数(代码相同)中,第32位有额外的1.

代码:

#include <iostream>

void printBits(long long number)
{
    std::cout<<number<<" -> ";
    for (char i=63; i>=0; --i)
    {
        std::cout<<(bool)(number&(1<<i));
    }
    std::cout<<std::endl;
}

int main()
{
    long long number=1;

    std::cout<<number<<" -> ";
    for (char i=63; i>=0; --i)
    {
        std::cout<<(bool)(number&(1<<i));
    }
    std::cout<<std::endl;

    printBits(number);

    return 0;
}

结果是:

1 -> 0000000000000000000000000000000000000000000000000000000000000001
1 -> 0000000000000000000000000000000100000000000000000000000000000001

Process returned 0 (0x0)   execution time : 0.012 s
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