小编Гош*_*ный的帖子

我正在尝试使用C和QEMU实现键盘中断处理程序。但是，当我执行程序时，我的处理程序仅打印一个字符。之后，处理程序将根本无法工作。

我的IDT设置：

struct IDT_entry {
    unsigned short int offset_lowerbits;
    unsigned short int selector;
    unsigned char zero;
    unsigned char type_attr;
    unsigned short int offset_higherbits;
};

void setup_idt() {
    struct IDT_entry IDT[256];
    unsigned long keyboard_address;
    unsigned long idt_address;
    unsigned long idt_ptr[2];

    keyboard_address = (unsigned long) keyboard_handler;
    IDT[0x21].offset_lowerbits = keyboard_address & 0xffff;
    IDT[0x21].selector = 0x8;
    IDT[0x21].zero = 0;
    IDT[0x21].type_attr = 0x8e;
    IDT[0x21].offset_higherbits = (keyboard_address & 0xffff0000) >> 16;

    /*
                PIC1   PIC2
    Commands    0x20   0xA0
    Data        0x21   0xA1

    */

    // ICW1 - init
    outb(0x20, …