简单的问题:我想将固定长度的字符串写入二进制文件(即二进制文件),如下面的代码片段所示。
写作“看起来”很好,但从文件中读取不起作用(编译和运行没有崩溃,但没有给出预期的结果)。
#include <iostream>
#include <fstream>
#include <string>
int main()
{
{
std::ofstream out {"out.dat", std::ios::binary};
//all of length 5
std::string a[] {{"12345"}, {"6789A"}, {"BCDEF"}};
//write down strings without \0
out.write(a[0].c_str(), a[0].length());
out.write(a[1].c_str(), a[1].length());
out.write(a[2].c_str(), a[2].length());
}
{
std::ifstream in {"out.dat", std::ios::binary};
std::string s2 {5, '\0'}; //I can store at least 5 chars
in.seekg(0 + 2 * 5); //try to read string of index 2
in.read(&s2[0], 5);
std::cout << s2 << std::endl; //prints "BC", not "BCDEF"
}
}
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最后一行应该恢复字符串“BCDEF”,但只打印“BC”(g++ 10.2.0)。 …
事情很简单,我想转发成员函数的调用及其参数,如以下代码段所述。
#include <iostream>
#include <functional>
template<class Function, class ... Args>
auto forward_args(Function&& f, Args&& ... args)
{
return f(std::forward<Args>(args)...);
}
int f(int i) { return i; }
struct A {
int get(int i) const { return i; }
};
int main()
{
std::cout << forward_args(f, 2) << std::endl; //ok
A a;
//std::cout << forward_args(&A::get, a, 2) << std::endl; //ko
static auto wrong_wrapper = &A::get;
//std::cout << forward_args(wrong_wrapper, a, 2) << std::endl; //ko again
static std::function<int …Run Code Online (Sandbox Code Playgroud)