我想像在引导代码中那样在PHP和HTML中创建一个不错的错误消息，而不是在echo（）中显示消息。但我不想使用任何功能来实现。
<?php
include 'condb.php';
if (isset($_POST['sub'])) {
$name = $_POST['name'];
$lname =$_POST['lname'];
$email =$_POST['email'];
$pass1 =$_POST['pass1'];
$pass2 =$_POST['pass2'];
if (empty($name) || empty($lname) || empty($email) || empty($pass1) ||
empty($pass2)) {
echo "<p class='alert alert-danger'> must fill all </p>";
}else{
if (empty($pass1) || empty($pass2)) {
echo "you must fill password";
}
else{
if ($pass1 == $pass2) {
$hashpass = md5($pass1);
$query="insert into users values (null, '$name', '$lname', '$email',
'$hashpass')";
$result=mysqli_query($conn,$query);
echo "success";
}else{
echo "passwords must be same";
}
}
}
} …