我需要输出一个JSON对象供iphone使用
我能输出像
{"feed":{"id":"1","player":"player1"}}
{"feed":{"id":"1","player":"player2"}}
{"feed":{"id":"2","player":"player3"}}
Run Code Online (Sandbox Code Playgroud)
代码 :
$query = "SELECT id,player FROM MyVideos";
$result = mysql_query($query,$link) or die('Errant query: '.$query);
$players[] = array();
if(mysql_num_rows($result)){
while($player = mysql_fetch_assoc($result)){
$players[] = array('player'=>$player);
echo json_encode(array("feed"=>$player));
}
}
Run Code Online (Sandbox Code Playgroud)
但我需要输出这样的东西
{"feed":
{"id":"1","player":"player1"},
{"id":"1","player":"player2"},
{"id":"2","player":"player3"}
}
Run Code Online (Sandbox Code Playgroud)
任何人都可以帮我这个.
谢谢,