我正在为Haskell中的Scheme解释器实现一个REPL,我想处理一些像UserInterrupt,StackOverflow,HeapOverflow等异步事件......基本上,我想在UserInterrupt发生时停止当前的计算并打印一个StackOverflow和HeapOverflow发生时的合适消息等.我实现如下:
repl evaluator = forever $ (do
putStr ">>> " >> hFlush stdout
out <- getLine >>= evaluator
if null out
then return ()
else putStrLn out)
`catch`
onUserInterrupt
onUserInterrupt UserInterrupt = putStrLn "\nUserInterruption"
onUserInterrupt e = throw e
main = do
interpreter <- getMyLispInterpreter
handle onAbort (repl $ interpreter "stdin")
putStrLn "Exiting..."
onAbort e = do
let x = show (e :: SomeException)
putStrLn $ "\nAborted: " ++ x
Run Code Online (Sandbox Code Playgroud)
它按预期工作,但有一个例外.如果我启动解释器并按Ctrl-Z + Enter,我会得到:
>>> ^Z
Aborted: <stdin>: hGetLine: end of …Run Code Online (Sandbox Code Playgroud) haskell exception-handling exception interruption read-eval-print-loop