小编dsc*_*bak的帖子

我有这样的json

{
    "name": "somenameofevent",
    "type": "event",
    "data": {
        "object": {
            "age": "18",
            "petName": "18"
        },
        "desct": {
        }
    }
}

我有2个像这样的对象

public class CustEvent
{
    [JsonProperty("name")]
    public string Name { get; set; }
    [JsonProperty("type")]
    public string EventType{ get; set; }
    [JsonProperty("data")]
    public SomeData Data{ get; set; }
}

public class SomeData
{
    [JsonProperty("object")]
    public String SomeObject { get; set;}
    [JsonProperty("dsct")]
    public String SomeDesct { get; set; }
}

我用来解析json对象Newtonsoft.NET库.以及如何将RAW JSON转换为SomeObject,SomeDesct属性？在JSON中,"data.object ..."是复杂的对象,我想只获得RAW JSON String到这些属性.你能帮助我吗 ？