我在w3schools上阅读了以下内容,我不明白第二部分意味着什么:
[全局变量]仍可用于加载到同一窗口中的新页面.
谁能开导我?
在Web浏览器中,当您关闭浏览器窗口(或选项卡)时,将删除全局变量,但仍可用于加载到同一窗口中的新页面.
我在本地主机上有一个名为webshop的数据库,其中有多个表。当我运行查询时:SELECT COUNT (userId) FROM users;
它引发以下错误:
FUNCTION webshop.COUNT does not exist. Check the 'Function Name Parsing and Resolution' section in the Reference Manual
我不知道为什么查询对我来说很好,有人吗?
我有以下 PHP 代码,它通过键名称搜索数组并返回等于搜索的结果。只是出于好奇,我该怎么做,无论我搜索什么结果都会是名称键值等于“A”的元素?很快我怎样才能检索名称为“A”的元素?
\n\n我尝试了以下方法,但 \xc2\xb4t 有效:
\n\n$jSearchResult[] = $ajProducts[$i]->name = "A";\nRun Code Online (Sandbox Code Playgroud)\n\n请帮助我,因为我只能\xc2\xb4t弄清楚如何通过键值检索数组的元素,但我确信它一定是非常简单的。
\n\n<?php\n\n//DATA coming from the BROWSER\n$sSearch = $_GET[\'search\'];\n//TURN it into UPPERCASE\nstrtoupper( $sSearch );\n\n//GETTING from the TEXT FILE:\n$sajProducts = file_get_contents( \'products.txt\' );\n$ajProducts = json_decode( $sajProducts );\n\n$match_found = false;\n//Collect all matching result in an array \n$jSearchResult = array();\n//LOOPING THROUGH THE ARRAY OF PRODUCTS\nfor ( $i=0; $i< count( $ajProducts ); $i++ ) {\n\n if ( $sSearch == $ajProducts[$i]->name ) {\n $jSearchResult[] = $ajProducts[$i]->name;\n $match_found = true; \n }\n}\n//if …Run Code Online (Sandbox Code Playgroud) 我有以下数组,我希望能够从JSON对象中删除所有“ phonenumber”键以及它的值。仅键“ phonenumber”不是整个对象。我怎样才能做到这一点?
[
{
"role": "admin",
"id": "59df4ef2d8d39",
"email": "a@a.dk",
"name": "A",
"lastname": "A",
"password": "1",
"image": "img_webshop\/userimage-59dfb91515810.png"
},
{
"role": "user",
"id": "59df4f1b070e6",
"phonenumber": "12345678",
"name": "B",
"lastname": "B",
"password": "2",
"image": "img_webshop\/userimage-59e37de69475b.png"
},
{
"role": "user",
"id": "59dfc0cb07985",
"email": "c@c.dk",
"name": "C",
"lastname": "C",
"password": "3",
"image": "img_webshop\/userimage-59dfc0cb06c5f.png"
},
{
"role": "user",
"id": "59dfc22f26f78",
"phonenumber": "87654321",
"name": "D",
"lastname": "D",
"password": "4",
"image": "img_webshop\/userimage-59dfc22f2638d.png"
},
{
"role": "user",
"id": "59dfc460b261e",
"email": "e@e.dk",
"name": "E",
"lastname": "E",
"password": …Run Code Online (Sandbox Code Playgroud)