我有WAMP服务器(2.1)的问题; 我有一些PHP文件,其中包含PHP语句
<? statements ?>
并且浏览器不解释代码.如果我使用:
<?php statements ?>
一切正常.
知道如何解决它.谢谢.
我有这个java代码,我想返回2个值,然后在main()或其他函数中使用它们.请帮忙.TX:
import java.net.*;
import java.io.*;
import java.io.File;
import org.apache.commons.io.FileUtils;
import org.apache.commons.lang.StringUtils;
public class URLReader {
public String[] functie(String x) throws Exception
{
URL oracle = new URL(x);
BufferedReader in = new BufferedReader(new InputStreamReader(oracle.openStream()));
String inputLine=null;
StringBuffer theText = new StringBuffer();
while ((inputLine = in.readLine()) != null)
theText.append(inputLine+"\n");
String html = theText.toString();
in.close();
String[] tds = StringUtils.substringsBetween(html, "<tr>", "</tr>");
String[] tds2 = StringUtils.substringsBetween(tds[1], "href=\"/module/gallery", "\"><img");
String[] tds3 = StringUtils.substringsBetween(tds[1], "src='/redx_tools/mb_image.php", "' border='1'");
return ???
}
public static void main(String[] args) throws …我想检查数据库中是否存在用户,如果存在则显示某些错误而不重新加载页面(修改div).知道这段代码有什么问题吗？或任何其他想法如何做到这一点？谢谢
HTML:
<div style="width:510px; height:500px;">
<div class="message">
<div id="alert"></div>
</div>
<form id="signup_form" method="post" action="register.php">
<label class="label">username</label>
<p><input class="signup_form" type="text" name="username"></p>
<label class="label">parola</label>
<p><input class="signup_form" type="text" name="password"></p>
<label class="label">name</label>
<p><input class="signup_form" type="text" name="name"></p>
<label class="label">telefon</label>
<p><input class="signup_form" type="text" name="phone"></p>
<label class="label">email</label>
<p><input class="signup_form" type="text" name="email"></p>
<p><input class="signup_button" type="submit" value="inregistrare">
</form>
<div class="clear"></div>
</div>
register.php
<?php
include "base.php";
$usertaken = '<li class="error">username used</li><br />';
$alert = '';
$pass = 0;
if(!empty($_POST['username']) && !empty($_POST['password']))
{
$username = mysql_real_escape_string($_POST['username']);
$password = md5(mysql_real_escape_string($_POST['password']));
$name = …