小编Rub*_*ben的帖子

假设我有这段代码:

class Stat {
   var statEvents : [StatEvents] = []
}

struct StatEvents {
   var name: String
   var date: String
   var hours: Int
}


var currentStat = Stat()

currentStat.statEvents = [
   StatEvents(name: "lunch", date: "01-01-2015", hours: 1),
   StatEvents(name: "dinner", date: "01-01-2015", hours: 1),
   StatEvents(name: "dinner", date: "01-01-2015", hours: 1),
   StatEvents(name: "lunch", date: "01-01-2015", hours: 1),
   StatEvents(name: "dinner", date: "01-01-2015", hours: 1)
]

var filteredArray1 : [StatEvents] = []
var filteredArray2 : [StatEvents] = []

我可以手动调用下一个函数,以便有两个按"同名"分组的数组.

filteredArray1 = currentStat.statEvents.filter({$0.name == "dinner"}) …

假设我有这段代码：

class Stat {
   var statEvents : [StatEvents] = []
}

struct StatEvents {
   var name: String
   var date: String
   var hours: Int
}

var currentStat = Stat()

currentStat.statEvents = [
   StatEvents(name: "lunch", date: "01-01-2015", hours: 1),
   StatEvents(name: "dinner", date: "02-01-2015", hours: 2),
   StatEvents(name: "dinner", date: "03-01-2015", hours: 3),
   StatEvents(name: "lunch", date: "04-01-2015", hours: 4),
   StatEvents(name: "dinner", date: "05-01-2015", hours: 5),
   StatEvents(name: "breakfast", date: "06-01-2015", hours: 6),
   StatEvents(name: "lunch", date: "07-01-2015", hours: 7),
   StatEvents(name: "breakfast", date: "08-01-2015", hours: 8)
] …