小编Har*_*tts的帖子

我希望能够使用包中的路由覆盖app/Http/routes.php中定义的路由.

例如,在app/Http/routes.php中,我可能会这样:

Route::get('/search/{type?}',['as' => 'search','uses' => 'SearchController@search']);

我希望能够在/vendor/author/package/src/Http/routes.php中定义它:

Route::get('/search/properties', ['as' => 'properties','uses' => 'PropertyController@search']);

首先加载app/Http/routes.php文件,以便使用它们中的路由,而不是包.

在Laravel 4中,我会使用App :: before或App :: after来做到这一点,给予他们优先权.

像包裹路线一样:

App::before(function() {
    Route::get('/search/properties', ['as' => 'properties','uses' => 'PropertyController@search']);
});

我不知道如何在Laravel 5中实现这一点.我发现这个https://mattstauffer.co/blog/laravel-5.0-middleware-filter-style,但不知道怎么用它来做我想要的.

编辑:Laravel 4执行此操作的方法将允许为每个路由设置此优先级,因此我不只是在应用程序之前加载所有包路由.

我正在尝试运行此查询：

$products = $this->product_model->where(function($query) use ($key) {
    $query->whereHas('categories', function ($category) use ($key) {
        $category->where('key', $key);
    });
    $query->orWhereHas('parent.categories', function ($category) use ($key) {
        return $category->where('key', $key);
    });
});

父关系是另一个产品，所以它来自同一个表。我遇到的问题在于它产生的查询：

SELECT *
FROM `products`
WHERE (
    (SELECT count(*)
     FROM `categories`
     INNER JOIN `category_product` ON `categories`.`id` = `category_product`.`category_id`
     WHERE `category_product`.`product_id` = `products`.`id`
     AND `key` = 'mens'
    ) >= 1
 OR
    (SELECT count(*)
     FROM `products` AS `self_30ec5d4782a83841add518f618b9f59e`
     WHERE `self_30ec5d4782a83841add518f618b9f59e`.`id` = `products`.`parent_product_id`
     AND
         (SELECT count(*)
          FROM `categories`
          INNER JOIN `category_product` ON `categories`.`id` = `category_product`.`category_id`
          WHERE …