Har*_*tts 5 php mysql laravel eloquent
我正在尝试运行此查询:
$products = $this->product_model->where(function($query) use ($key) {
$query->whereHas('categories', function ($category) use ($key) {
$category->where('key', $key);
});
$query->orWhereHas('parent.categories', function ($category) use ($key) {
return $category->where('key', $key);
});
});
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父关系是另一个产品,所以它来自同一个表。我遇到的问题在于它产生的查询:
SELECT *
FROM `products`
WHERE (
(SELECT count(*)
FROM `categories`
INNER JOIN `category_product` ON `categories`.`id` = `category_product`.`category_id`
WHERE `category_product`.`product_id` = `products`.`id`
AND `key` = 'mens'
) >= 1
OR
(SELECT count(*)
FROM `products` AS `self_30ec5d4782a83841add518f618b9f59e`
WHERE `self_30ec5d4782a83841add518f618b9f59e`.`id` = `products`.`parent_product_id`
AND
(SELECT count(*)
FROM `categories`
INNER JOIN `category_product` ON `categories`.`id` = `category_product`.`category_id`
WHERE `category_product`.`product_id` = `products`.`id`
AND `key` = 'mens'
) >= 1
) >= 1
)
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在 OR 之后的子查询中,我需要这一行:
WHERE `category_product`.`product_id` = `products`.`id`
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要这样:
WHERE `category_product`.`product_id` = `self_30ec5d4782a83841add518f618b9f59e`.`id`
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当我在数据库上运行这个 SQL 时,我得到了正确的结果:
SELECT *
FROM `products`
WHERE (
(SELECT count(*)
FROM `categories`
INNER JOIN `category_product` ON `categories`.`id` = `category_product`.`category_id`
WHERE `category_product`.`product_id` = `products`.`id`
AND `key` = 'mens'
) >= 1
OR
(SELECT count(*)
FROM `products` AS `self_30ec5d4782a83841add518f618b9f59e`
WHERE `self_30ec5d4782a83841add518f618b9f59e`.`id` = `products`.`parent_product_id`
AND
(SELECT count(*)
FROM `categories`
INNER JOIN `category_product` ON `categories`.`id` = `category_product`.`category_id`
WHERE `category_product`.`product_id` = `self_30ec5d4782a83841add518f618b9f59e`.`id`
AND `key` = 'mens'
) >= 1
) >= 1
)
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但我不确定如何在我的 PHP 代码中做到这一点。另外,这是预期的 SQL 输出吗?它不应该做我想让它做的事情吗?由于子查询在 whereHas?