小编div*_*uri的帖子

如何编写一个oracle查询,它等同于informix中的以下查询:

select tab1.a,tab2.b,tab3.c,tab4.d 
  from table1 tab1,
       table2 tab2 OUTER (table3 tab3,table4 tab4,table5 tab5) 
 where tab3.xya = tab4.xya 
   AND tab4.ss = tab1.ss 
   AND tab3.dd = tab5.dd 
   AND tab1.fg = tab2.fg 
   AND tab4.kk = tab5.kk 
   AND tab3.desc = "XYZ"

我试过:

select tab1.a,tab2.b,tab3.c,tab4.d 
  from table1 tab1,
       table2 tab2 LEFT OUTER JOIN (table3 tab3,table4 tab4,table5 tab5) 
 where tab3.xya = tab4.xya 
   AND tab4.ss = tab1.ss 
   AND tab3.dd = tab5.dd 
   AND tab1.fg = tab2.fg 
   AND tab4.kk = tab5.kk 
   AND tab3.desc = "XYZ"

任何人都可以帮助我获得正确的语法.

我试图从jboss 4在jboss 7中运行我的应用程序.在jboss 4中,我们更改了server.xml以配置keystoreFile和keystorePass等.任何人都可以帮助我在jboss7中进行这些更改.

我正在尝试将Informix查询转换为Oracle:

Informix查询如下所示:

SELECT
    r.aa, n.bb, nd.cc,u.id, ud.dd, g.attr 
FROM
    tab1 u, tab2 ud, 
OUTER (tab3 a, tab4 n, tab5 nd, tab6 r, OUTER (tab7 g, tab8 atr))
WHERE
    r.xx = n.xx AND
    n.nas = a.nas AND
    a.user = u.user AND
    a.ac = g.ac AND
    n.nas1 = nd.nas1 AND
    u.user1 = ud.user1 AND
    atr.sso = g.sso AND
    UPPER(atr.name) = 'NAME' AND
    u.id = 102 

Oracle查询如下所示:

SELECT
    r.aa, n.bb, nd.cc,u.id, ud.dd, g.attr
FROM
    tab1 u
INNER JOIN tab2 ud ON
    u.user1 = …

我下载了JBoss AS 7并尝试在其中运行我的应用程序.但我找不到server.xml更改设置.以前我使用JBoss AS 4.2.2并有server.xml在<jboss_home>\server\default\deploy\jboss-web.deployer.任何人都可以帮我如何配置AS 7？