小编Mik*_*ris的帖子

我怎样才能转换char* argv[]为wstring？我用来"/d"获取字符串路径argv并将其作为函数的参数插入ArrayOfDirContents。

int main(int argc, char *argv[])
{
    double minimum = 10;
    double input;
    char* filename;
    wstring adr(L".");
    const wchar_t* adresar; 

    adresar = adr.c_str();

    char *p;

    int num;


    errno = 0;
    long conv;

    for (unsigned i = 1; i < argc; i++) {   
        conv = strtol(argv[i], &p, 10);

        // Check for errors: e.g., the string does not represent an integer
        // or the integer is larger than int
        if (errno …