我有这个代码:
// basic file operations
#include <iostream>
#include <fstream>
using namespace std;
int main()
{
writeFile();
}
int writeFile ()
{
ofstream myfile;
myfile.open ("example.txt");
myfile << "Writing this to a file.\n";
myfile << "Writing this to a file.\n";
myfile << "Writing this to a file.\n";
myfile << "Writing this to a file.\n";
myfile.close();
return 0;
}
Run Code Online (Sandbox Code Playgroud)
为什么这不起作用?它给了我错误:
1>------ Build started: Project: FileRead, Configuration: Debug Win32 ------
1> file.cpp
1>e:\documents and settings\row\my documents\visual studio 2010\projects\fileread\fileread\file.cpp(8): error C3861: 'writeFile': identifier not …Run Code Online (Sandbox Code Playgroud) 我对preg_replace有点问题.我需要一个函数将所有字符转换为除了[A-z][0-9]和之外的所有字符. ! ?
我可以做一个preg_match,但这只是验证,我想要被替换.这不把垃圾字符像
<p>和;[[;[p;[
在描述元标记.
所以脚本必须像:
;")<br>kk23?! => brkk23?!
任何帮助将不胜感激:D
这个代码有点问题.脚本连接,但它不会给我位于根目录中的文件夹...我错过了什么?
$ftp_server = "ftp.something.com";
$ftp_user = "user";
$ftp_pass = "pass";
// set up a connection or die
$conn_id = ftp_connect($ftp_server) or die("Couldn't connect to $ftp_server");
// try to login
if (@ftp_login($conn_id, $ftp_user, $ftp_pass))
{
echo "Connected as $ftp_user@$ftp_server\n";
}
else
{
echo "Couldn't connect as $ftp_user@$ftp_server\n";
}
$contents = ftp_nlist($conn_id, ".");
var_dump($contents);
ftp_close($conn_id);
die;
Run Code Online (Sandbox Code Playgroud)
它输出
Connected as $ftp_user@$ftp_server;
Run Code Online (Sandbox Code Playgroud)
和
boolean false
Run Code Online (Sandbox Code Playgroud)
为什么它不会列出文件?
我可以非常快速地解决这个问题
file_exists("ftp//user:pass@host.com")
Run Code Online (Sandbox Code Playgroud)
......但是容易的部分不是我想要的东西,我什么都不会学到
Microsoft Windows [Version 6.1.7600]
Copyright (c) 2009 Microsoft Corporation. All rights reserved.
E:\Windows\system32>heroku login
Enter your Heroku credentials.
Email: mymail@yahoo.com
Password (typing will be hidden):
Found existing public key: E:/Users/Stewie/.ssh/id_rsa.pub
Uploading SSH public key E:/Users/Stewie/.ssh/id_rsa.pub... failed
! Fingerprint already exists. Please use one SSH key per Heroku account
E:\Windows\system32>git clone git@heroku.com:sharp-winter-5732.git -o heroku
Cloning into 'sharp-winter-5732'...
! Your key with fingerprint f2:a2:f9:4a:c4:16:5b:f1:5a:21:cb:d8:c4:d2:18:ef is
not authorized to access sharp-winter-5732.
fatal: The remote end hung up unexpectedly
E:\Windows\system32>
Run Code Online (Sandbox Code Playgroud)
为什么我一直有这个错误?我该怎么办?并且不要给我一个减号,因为我已经看过了
https://help.github.com/articles/set-up-git
并给了我
E:\Windows\system32>git …Run Code Online (Sandbox Code Playgroud) 我有以下json
country_code({"latitude":"45.9390","longitude":"24.9811","zoom":6,"address":{"city":"-","country":"Romania","country_code":"RO","region":"-"}})
Run Code Online (Sandbox Code Playgroud)
我只想要country_code,我如何解析它?
我有这个代码
<?php
$json = "http://api.wipmania.com/jsonp?callback=jsonpCallback";
$jsonfile = file_get_contents($json);
var_dump(json_decode($jsonfile));
?>
Run Code Online (Sandbox Code Playgroud)
它返回NULL,为什么?
谢谢.
我有一个小问题,有没有办法动态包含另一个xsl?例如:
<xsl:variable name="PathToWeb" select="'wewe'"/>
<xsl:include href="http://{$PathToWeb}/html/xsl/head.xsl" />
<xsl:include href="http://{$PathToWeb}/html/xsl/navigation.xsl" />
<xsl:include href="http://{$PathToWeb}/html/xsl/promo.xsl" />
<xsl:include href="http://{$PathToWeb}/html/xsl/3columns.xsl" />
<xsl:include href="http://{$PathToWeb}/html/xsl/footer.xsl" />
Run Code Online (Sandbox Code Playgroud) 我有以下结构
user_id int(11)
right int(11)
group_id int(11)
value tinyint(1)
Run Code Online (Sandbox Code Playgroud)
还有3个查询
INSERT INTO user_rights (`user_id`,`right`,`group_id`,`value`)
VALUES ( '42', '160', '1', '1' );
INSERT INTO user_rights ('user_id','right','group_id','value')
VALUES ( '42', '160', '1', '1' );
INSERT INTO user_rights (user_id,right,group_id,value)
VALUES ( '42', '160', '1', '1' );
Run Code Online (Sandbox Code Playgroud)
解释我为什么只有第一个有效????
我的一生都在使用第三个!
谢谢.
我在stackoverflow上看到了一些关于如何检查电子邮件是否存在的教程,我不太明白如何...
方法1
基本上我必须在cmd.exe中运行以下命令
telnet gmail-smtp-in.l.google.com 25
helo
mail from: <youremail@gmail.com>
rcpt to: <mailtocheck4@gmail.com>
Run Code Online (Sandbox Code Playgroud)
如果回复是"OK",那么我们会收到一封好的电子邮件.我在.bat文件中插入了所有这些内容,bat文件所做的只是连接到telnet并完成...
方法2
使用这个 http://www.geckotribe.com/php-telnet/#usage连接到telnet,但我不知道我应该提供什么密码
<?php
require_once "PHPTelnet.php";
$telnet = new PHPTelnet();
// if the first argument to Connect is blank,
// PHPTelnet will connect to the local host via 127.0.0.1
$result = $telnet->Connect('mail.gmail.com','usr','password');
if ($result == 0)
{
$telnet->DoCommand('helo', $result);
// NOTE: $result may contain newlines
echo $result;
$telnet->DoCommand('another command', $result);
echo $result;
// say Disconnect(0); to break the connection without explicitly logging out …Run Code Online (Sandbox Code Playgroud) 我有一个小问题......这是我的xml:
<?xml version="1.0" encoding="UTF-8"?>
<links>
<link>
<id>432423</id>
<href>http://www.google.ro</href>
</link>
<link>
<id>5432345</id>
<href>http://www.youtube.com</href>
</link>
<link>
<id>5443</id>
<href>http://www.yoursite.com</href>
</link>
</links>
Run Code Online (Sandbox Code Playgroud)
我怎么能和另一个人说话
<link>
<id>5443</id>
<href>http://www.yoursite.com</href>
</link>
Run Code Online (Sandbox Code Playgroud)
??
我设法只使用xpath向ROOT/LINKS添加记录 - > LINK,这是代码
<?php
$doc = new DOMDocument();
$doc->load( 'links.xml' );
$links= $doc->getElementsByTagName("links");
$xpath = new DOMXPath($doc);
$hrefs = $xpath->evaluate("/links");
$href = $hrefs->item(0);
$item = $doc->createElement("item");
/*HERE IS THE ISSUE...*/
$link = $doc->createElement("id","298312800");
$href->appendChild($link);
$link = $doc->createElement("link","www.anysite.com");
$href->appendChild($link);
$href->appendChild($item);
print $doc->save('links.xml');
echo "the link has been added!";
?>
Run Code Online (Sandbox Code Playgroud)
任何帮助将不胜感激:D
好吧,我在视频/学校的java学习中作为初学者编写了这段代码,我得到了一些问题.
1 =>为什么文件>退出按钮不起作用并且有一个小箭头,好像有一些孩子一样?大退出按钮使用相同的功能.我从这里受到启发:http://www.youtube.com/watch? src_vid = FB_wJpIdA8k&feature = iv&annotation_id = annotation_40248&v = dwLkDGm5EBc
2 =>如何让该按钮变小?当我调整它时,它会更大.
3 =>有谁知道一个简单的声音播放器库?那么当我按下那个按钮播放声音时?我已尝试过一些网络示例,例如http://www.developer.com/java/other/article.php/2173111/Java-Sound-Playing-Back-Audio-Files-using-Java.htm并且不知道如何使它变得简单,并在SoundPlay(sound.au)等各处使用它;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JMenu;
import javax.swing.JMenuBar;
import javax.swing.JMenuItem;
public class form4
{
public static void main(String[] args)
{
// Frame
JFrame frame = new JFrame("Menu");
frame.setSize(300,300);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
// Just create menubar
JMenuBar menubar = new JMenuBar();
frame.setJMenuBar(menubar);
// Add an JMenu
JMenu file = new JMenu("File");
menubar.add(file); …Run Code Online (Sandbox Code Playgroud) 使用PHP和Dom Document创建复杂的XML结构时遇到了一些问题.
我希望结构是这样的:
<page PathToWeb="www.mysite.com">
<Questions>
<Question id="my id" member="true">
<Question id="my id2" member="true">
<Question id="my id3" member="true">
</Questions>
</page>
Run Code Online (Sandbox Code Playgroud)
我到目前为止的代码是
<?php
/*Create DOM*/
$xml = new DOMDocument;
$xml->load('myxml.xml'); /* wich is just just blank <?xml?\> <page> </page>*/
$xpath = new DOMXPath($xml);
/*Set the base path*/
$hrefs = $xpath->evaluate("/page");
/*Add Path to web to the root /page*/
$href = $hrefs->item(0);
$href->setAttribute("PathToWeb",$PathToWeb);
/*Complex XML Creation with Xpath*/
/*ELEMENT APPEND (create questions into /page)*/
$href = $hrefs->item(0);
$element = $xml->createElement('Questions');
$href->appendChild($element);
/*XPATH …Run Code Online (Sandbox Code Playgroud) 我没有完全理解线程的概念我有一些问题.假设我们有以下代码:
ExecCommand.java
// I don't know how this work, for now
package therads;
// Here we will have the methods and run them from the Main.java
public class ExecCommand implements Runnable
{
String name;
int time;
public ExecCommand(String s,int amount)
{
name = s;
time = amount;
}
// Run method (Runnable)
public void run()
{
try
{
// What to execute when the thread is started
System.out.printf("%s is sleeping for %d\n",name,time);
Thread.sleep(time);
System.out.printf("%s is done\n",name);
}
catch(Exception e)
{ …Run Code Online (Sandbox Code Playgroud)