我需要查找并计算字符串中可以找到多少个字符.我已将字符分为chars1 [a:m]和chars2 [n:z],并有两个计数器.
输出应为0/14,但它是0/1.我认为它只检查是否包含一个且只有一个项目,然后退出循环.是这样的吗？
这是代码.
string_1 = "aaabbbbhaijjjm"
def error_printer(s):
chars1 = "abcdefghijklm"
chars2 = "nopqrstuvwxyz"
counter1 = 0
counter2 = 0
if ((c in s) for c in chars1):
counter1 += 1
elif ((c in s) for c in chars2):
counter2 += 1
print(str(counter2) + "/" + str(counter1))
error_printer(string_1)