我正在阅读Effective C++(Scott Meyers),并在尝试编译本书中的以下代码时得到错误"与运算符*不匹配":
rational.h
class rational
{
private:
int num;
int den;
public:
rational(int n = 0, int d = 1);
int getNum() const {return num;}
int getDen() const {return den;}
};
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rational.cpp
#include "rational.h"
rational::rational(int n,
int d)
:num(n),
den(d)
{}
const rational operator*(const rational &lhs,
const rational &rhs)
{
return rational( lhs.getNum()*rhs.getNum(),
lhs.getDen()*rhs.getDen() );
}
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main.cpp中
#include "rational.h"
int main()
{
rational r1(1,2);
rational r2;
r2 = 2*r1;
r2 = r1*3;
return 0;
}
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有人可以解释为什么会这样吗?
我有这样的代码
<img onclick="getTitle();" title="myimg" >
function getTitle()
{
alert(jQuery(this).attr("title");
}
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它不起作用.有人可以解释如何做到这一点.这段代码出了什么问题.