小编Pau*_*van的帖子

我有这个问题:

SELECT * FROM `employee_activities` a
LEFT JOIN `activity` b ON a.activity_code = b.code
LEFT JOIN `employees` c ON a.employee_code = c.code
WHERE b.type = "Design"
AND c.code NOT IN(
    SELECT * FROM `employee_activities` a
        LEFT JOIN `activity` b ON a.activity_code = b.code
        LEFT JOIN `employees` c ON a.employee_code = c.code
        WHERE b.type = "Testing"
)
GROUP BY c.code

我收到此错误:

#1241 - Operand should contain 1 column(s)

我想要让所有至少有一个类型为"设计"活动且没有活动类型为"测试"的员工.

我有一个有效的查询,但我希望它可以使用连接.

这有效:

SELECT c.name FROM `employee_activities` a, `activity` b, `employees` c
WHERE …

错误是:

System.Data.dll中发生未处理的"System.Data.SqlClient.SqlException"类型的异常
附加信息:关键字"User"附近的语法不正确.

代码是:

using System;  
using System.Collections.Generic;  
using System.ComponentModel;  
using System.Data;  
using System.Drawing;  
using System.Linq;  
using System.Text;  
using System.Windows.Forms;  
using System.Data.SqlClient;  

namespace WindowsFormsApplication1  
{  
    public partial class Form1 : Form  
    {  
        SqlConnection conn;  
        SqlDataAdapter GameDA;  
        SqlDataAdapter DetailDA;  
        DataSet DetailDS;  
        SqlCommandBuilder cmdBuilder;  
        SqlDataAdapter UserDA;  
        SqlDataAdapter AdministratorDA;  
        SqlDataAdapter OrderDA;  
        DataSet OrderDS;  
        SqlCommandBuilder cmdBuilder2;  

        public Form1()
        {
            InitializeComponent();
            conn = new SqlConnection("Data Source=HOME-AC284121FE\\SQLEXPRESS;Initial Catalog=GameShop;Integrated Security=SSPI;");
            SqlCommand command1 = new SqlCommand("SELECT * FROM Game", conn);
            GameDA = new SqlDataAdapter(command1);
            SqlCommand command2 = new …

我知道互联网上有很多方法,但这种情况很特殊.

我需要更换:)用<img src="smiley.gif">.和

str.replace(/:)/g,'img src="smiley.gif"')

不起作用!请帮帮我!

我有2个B和D类.我必须创建一个包含4个B类型元素2和2个D类型的数组.我该怎么办？

B o1 = new B();
D o2 = new D();
B o3 = new B();
D o4 = new D();

数组应该是这样的:

array[0] = o1; array[1] = o2; array[2] = o3; array[3] = o4;