当函数与解构一起使用时返回正确的预期值:
[{"k":"key1","v":"val1"},{"k":"key2","v":"val2"},{"k":"key3","v":"val3"}]
console.log(JSON.stringify([{
k: 'key1',
v: 'val1',
z: 'z1'
}, {
k: 'key2',
v: 'val2',
z: 'z2'
}, {
k: 'key3',
v: 'val3',
z: 'z3'
}].map(function(x) {
let {k, v} = x;
return {k, v };
})));Run Code Online (Sandbox Code Playgroud)
但是,当 lambda 函数与解构一起使用时,返回的值不正确:
[{"k":"key1","v":"val1","z":"z1"},{"k":"key2","v":"val2","z":"z2"},{"k":"key3","v":"val3","z":"z3"}]
console.log(JSON.stringify([{
k: 'key1',
v: 'val1',
z: 'z1'
}, {
k: 'key2',
v: 'val2',
z: 'z2'
}, {
k: 'key3',
v: 'val3',
z: 'z3'
}].map(x =>
({k, v} = x) )));Run Code Online (Sandbox Code Playgroud)
我如何在 lambda 函数内部使用解构,使其返回与function()上面使用显式相同的结果?