lambda 函数中的解构返回意外值

Question

当函数与解构一起使用时返回正确的预期值：
[{"k":"key1","v":"val1"},{"k":"key2","v":"val2"},{"k":"key3","v":"val3"}]

console.log(JSON.stringify([{
  k: 'key1',
  v: 'val1',
  z: 'z1'
}, {
  k: 'key2',
  v: 'val2',
  z: 'z2'
}, {
  k: 'key3',
  v: 'val3',
  z: 'z3'
}].map(function(x) {
  let {k, v} = x;
  return {k, v };
})));

但是，当 lambda 函数与解构一起使用时，返回的值不正确：
[{"k":"key1","v":"val1","z":"z1"},{"k":"key2","v":"val2","z":"z2"},{"k":"key3","v":"val3","z":"z3"}]

    console.log(JSON.stringify([{
      k: 'key1',
      v: 'val1',
      z: 'z1'
    }, {
      k: 'key2',
      v: 'val2',
      z: 'z2'
    }, {
      k: 'key3',
      v: 'val3',
      z: 'z3'
    }].map(x => 
      ({k, v} = x) )));

我如何在 lambda 函数内部使用解构，使其返回与function()上面使用显式相同的结果？

Answer 1

您可以在回调的参数内部使用解构Array#map

let array = [{ k: 'key1', v: 'val1', z: 'z1' }, { k: 'key2', v: 'val2', z: 'z2' }, { k: 'key3', v: 'val3', z: 'z3' }];

console.log(array.map(({ k, v }) => ({ k, v })));

.as-console-wrapper { max-height: 100% !important; top: 0; }