小编Lok*_*rki的帖子

我想使用我在 firebase 中的链接数据打开一堆音乐应用程序链接。我想打开，amazonPrimeMusic、Ganna、Spotify、Wynk、JioSavaan 等等。

Widget buildResultCard(data) {
  List items = [Text(data['Ganna']),
    IconButton(icon:Icon(Icons.all_inclusive),
      onPressed: ()=> {Text("Ganna")}
    ),

    Text(data['Wynk']),
    IconButton(icon:Icon(Icons.all_inclusive),
      onPressed: ()=> {Text("Ganna")}
    ),

    Text(data['JioSavaan']),
    IconButton(icon:Icon(Icons.all_inclusive),
      onPressed: ()=> {Text("Ganna")}
    ),

    Text(data['PrimeMusic']),
    IconButton(icon:Icon(Icons.all_inclusive),
      onPressed: ()=> {Text("Ganna")}
    )
  ];

  return ListView.builder(
    padding: EdgeInsets.only(top: 20),
    itemCount: items.length,
    itemBuilder: (BuildContext context, int index) {
      return items[index];
    },
  );
}

当我点击列表中的按钮时，它应该打开链接所在的特定应用程序，例如 AmazonPrimeMusic 链接，它应该打开亚马逊音乐应用程序。