小编Lyn*_*dey的帖子

以下查询每个ID返回两行.

select distinct ID,
count (COURSE_IDENTIFICATION) as tot_course_id,

COUNT(case when course_level = 'G'
     then (COURSE_IDENTIFICATION)
     else '0'end) count_grad,

COUNT (case when course_level = 'U'
       then (COURSE_IDENTIFICATION)
       else '0'end) count_under

from ods.STUDENT_COURSE

where ACADEMIC_PERIOD = '201890'
and COURSE_BILLING_CREDITS >0.0
group by ID, course_level
order by 1

我收到以下结果:

ID      |TOT_COURSE_NUM |COUNT_GRAD |COUNT_UNDER
-------------------------------------------------
12345   |1              |1          |1
12345   |2              |2          |2

有没有办法确保同一行中的grad和undergrad总数都计算在内？