小编Aja*_*ngh的帖子

我无法在ajax.Getting Uncaught TypeError: Cannot read property 'customers' of undefined错误中使用jquery获取JSON数据.

<script type="text/javascript">

$("#savechanges").click(function(e) {
e.preventDefault();


jQuery.ajax({
url: "<?=base_url()?>customers/updatecustomerorderdetail",
data: $('#savecustomer input').serialize(),
type: "POST",
dataType: 'json',
beforeSend: function() {
        //$("#update_"+id).html('');
        $("#savechanges").html('<i class="fa fa-spinner fa-spin"></i>updating...');

       },
success:function(data){

        var customer_name = data[0].customers[0].customer_name;

        alert(customer_name);

        console.log(data);


 },
error:function (error){

    console.log(error);
}

});

});

来自上面代码的JSON响应

{  
 "customers":[  
   {  
     "customer_id":22,
     "customer_name":"fggfd",
     "customer_email":"fggd",
     "customer_mobile":"dfgf",
     "updated_user_id":"5",
     "updated_datetime":"2018-07-30 21:00:57"
  }
]
}

我想customer_name从ajax的成功函数中的JSON数据中提醒.任何人都可以告诉我这里做错了什么？