小编Nic*_*den的帖子

我正在尝试从另一个组件进行sidenav切换，但是当从我的父组件调用.toggle（）函数时，它将引发此错误：

AppComponent.html：1错误TypeError：AppComponent.webpackJsonp.176.AppComponent.toggleNav中的this.sidenav.toggle不是函数（app.component.ts：25）

这是代码：app.component.ts

import { Component, ViewChild } from '@angular/core';
import { MaterialModule } from '@angular/material';
import { NavComponent } from './nav/nav.component';
import { SidebarComponent } from './sidebar/sidebar.component';
import { FooterComponent } from './footer/footer.component';
import { MdSidenav } from '@angular/material';
@Component({
    moduleId: module.id,
    selector: 'app-root',
    templateUrl: './app.component.html',
    styleUrls: ['./app.component.scss']
})
export class AppComponent{
    title = 'CRS Management App';
    @ViewChild('sidenav') sidenav:MdSidenav;
    toggleNav(){
      this.sidenav.toggle();
    }
}

app.component.html：

<app-nav #navbar (nav)="toggleNav()"></app-nav>
<app-sidebar #sidenav></app-sidebar>
<app-footer></app-footer>

（nav）从app-nav组件发出。

sidebar.component.ts：

@Component({
  selector: 'app-sidebar',
  templateUrl: './sidebar.component.html',
  styleUrls: ['./sidebar.component.scss'] …

I am trying to dynamically split an array of objects into groups based on values of a property.

Here is an example of the input:

`input = [
    {"name": "john", "location": "first"},
    {"name": "steve", "location": "first"},
    {"name": "paul", "location": "another"},
    {"name": "tony", "location": "random"},
    {"name": "ant", "location": "random"}
]`

and the desired output:

`solution(input, location) = [
    first:   [{"name": "john", "location": "first"},
              {"name": "steve", "location": "first"}],
    another: [{"name": "paul", "location": "another"}],
    random:  [{"name": "tony", "location": "random"},
              {"name": "ant", "location": "random"}] …

在 Model.insertMany 的文档中，它说当 options.ordered == true 时，该方法将在第一个错误时失败。

https://mongoosejs.com/docs/api.html#model_Model.insertMany

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[options.ordered \xc2\xabBoolean\xc2\xbb = true] 如果为 true，则在遇到第一个错误时快速失败。如果为 false，将插入它可以插入的所有文档并稍后报告错误。ordered = false 的 insertMany() 称为“无序”insertMany()。

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可以：

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• 出现错误并且没有向数据库写入任何文档。（我想要什么）
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或者

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• 写文件之前发生的错误，有错误，然后不再写文件？
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