我是一名熟练的Visual Basic程序员.我想了解人们如何编程硬件.例如,我见过人们制造LED手表,盒子等.你是如何实现这一目标的?可以使用VB或Java完成吗?我在阅读C,C++代码方面有一些经验.我只知道C和C++语言中的IO.
上一个问题:为什么数据没有插入到我的数据库中?
收到当前错误:
INSERT command denied to user ''@'localhost' for table 'all'
这是PHP/HTML代码,
<?php
/*
Assignment Form
by Rohan Verma,
alias RHNVRM.
*/
// Initialisation
include('config.php');
// End Initialisation
?>
<!DOCTYPE html>
<html>
<head>
<!-- ... -->
<title>Assignment</title>
</head>
<body>
<form action="submit.php" method="post">
<label>Roll No:</label>
<select name="roll">
<optgroup label="Choose your Roll Number">
<?php
// Generator for options
for ($i = 1; $i <= 20; $i++) {
echo "<option value = '$i'>$i</option>";
}
//End
?>
</optgroup>
</select>
<label>Your Name: …Run Code Online (Sandbox Code Playgroud) 我正在构建一个图像幻灯片.目前,我已将事件附加到H1元素.这是我的代码存储在文件main.js夹中的文件中jq: -
(function($) {
$.fn.browseImages = function(type) {
var image = [];
image[3] = "http://farm5.static.flickr.com/4006/5131022085_62876bbfbd_b.jpg";
image[2] = "http://farm6.static.flickr.com/5201/5289991939_46a20dd9fd_o.jpg";
image[1] = "http://farm3.static.flickr.com/2127/5807551517_72d39a1d19_b.jpg";
var imageObject = $(this);
var selection;
if (type == "left") {
for (var i=1; i < image.length; i++) {
if (imageObject.attr("src") == image[i]) {
selection = i + 1;
}
}
imageObject.attr("src",image[selection]);
} else {
for (var i=1; i < image.length; i++) {
if (imageObject.attr("src") == image[i]) {
selection = i + 1;
} …Run Code Online (Sandbox Code Playgroud) 这是我的jsfiddle(http://jsfiddle.net/mZGsp/).我试图在这里回答一个问题,但我的代码不起作用.这是代码:
var stateOfClick = null;
function initiateLine(){
document.getElementById('test').innerHtml = "Started";
}
function endLine(){
document.getElementById('test').innerHtml = "Line Ended";
}
function createLines(){
if(!stateOfClick) {
initiateLine();
stateOfClick = 1;
} else {
endLine();
}
}
Run Code Online (Sandbox Code Playgroud)
<body>
<input type="text" id="test" onclick="createlines()">
</body>
Run Code Online (Sandbox Code Playgroud) 我的编译器没有编译我编写的以下程序.它给出了我标记为"标识符未声明"的行的错误,即使我已经在我的Main()函数中声明了它.
该程序不完整,但它将接受有关活动的输入并输出它.
#include <iostream.h>
#include <conio.h>
void addToLog();
void viewLog();
void what()
{
cout << "What would you like to do?" << endl
<< "1. View Today's Log" << endl
<< "2. Add to Today's Log" << endl
<< "__________________________" << endl << endl
<< "? -> ";
int in;
cin >> in;
if ( in == 1 )
{
viewLog();
}
if ( in == 2 )
{
addToLog();
}
}
void main()
{
clrscr();
struct database
{
char …Run Code Online (Sandbox Code Playgroud)