小编bek*_*kks的帖子

使用Oracle SQL获取unix纪元时间戳的人是否有更好更快的解决方案？:

SQL> select (cast(sysdate as date) - cast(to_date('1970-01-01', 'YYYY-MM-DD') as date)) * 86400 as unixepoch from dual;

 UNIXEPOCH
----------
1490789604;

Oneliner首选;)