小编Nab*_*l B的帖子

我正在尝试在pyplot中添加一个按钮到我的窗口,就像在matplotlib.widgets的文档中给出的示例,我不能发布漏洞代码(SO的限制),但我认为问题在于标题

import matplotlib

import numpy as np
matplotlib.use('TkAgg')
from matplotlib.backends.backend_tkagg import FigureCanvasTkAgg, NavigationToolbar2TkAgg
import matplotlib.pyplot as plt
from matplotlib.widgets import Slider, RadioButtons, Button

import time
import random
import sys
from tkinter import *

import matplotlib.animation as animation
import matplotlib.pyplot as plt

并按钮实例化如下:

class Index(object):
    ind = 0

    def next(self, event):
        self.ind += 1
        print("just pressed next")

callback = Index()
axprev = plt.axes([0.7, 0.05, 0.1, 0.075])
axnext = plt.axes([0.81, 0.05, 0.1, 0.075])
bnext = Button(axnext, 'Next')
bnext.on_clicked(callback.next)
bprev = Button(axprev, 'Previous') …