小编And*_*024的帖子

我正在开发一个 React-Native 应用程序，它是当前 Web 应用程序的扩展。Web 应用程序使用 MSAL 对用户进行身份验证，我也想通过移动应用程序执行此操作。

我还没有真正找到任何相关的东西，而且我发现的东西已经过时了，或者对于 ReactJS 框架来说已经过时了。

我一直在尝试使用 MSAL-react-native 组件，但它没有很好的记录，所以我也迷失了方向

As with regards to python, when it comes to a for loop, will it re-evaluate the upper bound before re-iteration?

Say I have the following scenario:

def remove(self,list,element):
     for x in range(0,len(list)):
           if somecondition:
               list.pop(x)

Will the len(list) condition be re-evaluated before executing the next iteration of the for loop? (As done in some languages such as Objective-C I believe) As otherwise if a number of elements is popped, an out of bounds error would arise if say 1 element …

出于某种原因,eclipse在npcname_m [0] ="steve"中一直给我一个']'错误;

    String npcname_m[]=new String[10];
    npcname_m[0]="Steve";
    npcname_m[1]="John";
    npcname_m[2]="Mark";
    npcname_m[3]="Andrew";
    npcname_m[4]="Matthew";
    npcname_m[5]="Luke";
    npcname_m[6]="Miguel";
    npcname_m[7]="Michael";
    npcname_m[8]="Josh";
    npcname_m[9]="Alex";

整个代码

public class npc
{
    //NPC Types; Speci
    public enum npctype{villager, mob, special, hostile, passive, placeholder}
    npctype npc_type =npctype.placeholder;
    String npcname_m[]=new String[10];
    npcname_m[0]="Steve";
    npcname_m[1]="John";
    npcname_m[2]="Mark";
    npcname_m[3]="Andrew";
    npcname_m[4]="Matthew";
    npcname_m[5]="Luke";
    npcname_m[6]="Miguel";
    npcname_m[7]="Michael";
    npcname_m[8]="Josh";
    npcname_m[9]="Alex";

    String[] npcname_f = new String[10];
    npcname_f[0]="Mariah";
    npcname_f[1]="Joyce";
    npcname_f[2]="Kaede Akamatsu";
    npcname_f[3]="Iruma Miu";
    npcname_f[4]="Maki";
    npcname_f[5]="Hannah";
    npcname_f[6]="Angie";
    npcname_f[7]="Grace";
    npcname_f[8]="Melissa";
    npcname_f[9]="Alex";

    public enum npcclass{weak, strong, rare}
    String name = "Placeholder to avoid problems with garbage collector"; …