小编d4n*_*4ne的帖子

C#从反序列化的json对象获取值

我目前正在使用Newtonsoft.Json nuget数据包使用以下代码反序列化json字符串:

var data = (JObject)JsonConvert.DeserializeObject(json);
Run Code Online (Sandbox Code Playgroud)

现在,我收到以下格式的对象:

{{  "meta": {    "rap": 2098,    "count": 5  },  "data": [    {      "name": "Gold Tetramino of Mastery",      "rap": 735,      "uaid": "16601901",      "link": "https://www.roblox.com/Gold-Tetramino-of-Mastery-item?id=5786047",      "img": "https://t4.rbxcdn.com/081337d7ea86e6a406512aaa83bbcdeb",      "serial": "---",      "count": 1    },    {      "name": "Silver Tetramino of Accomplishment",      "rap": 385,      "uaid": "16601900",      "link": "https://www.roblox.com/Silver-Tetramino-of-Accomplishment-item?id=5786026",      "img": "https://t1.rbxcdn.com/60da69cd76f8dad979326f63f4a5b657",      "serial": "---",      "count": 1    },    {      "name": "Subzero Ski Specs",      "rap": 370,      "uaid": "155175547",      "link": "https://www.roblox.com/Subzero-Ski-Specs-item?id=19644587",      "img": "https://t4.rbxcdn.com/8ead2b0418ef418c7650d34103d39b6d",      "serial": "---",      "count": 1    },    {      "name": "Rusty Tetramino of Competence",      "rap": …
Run Code Online (Sandbox Code Playgroud)

c# json

5
推荐指数
3
解决办法
1万
查看次数

标签 统计

c# ×1

json ×1