vector<int> input = {1, 2, 3, 4, 17, 117, 517, 997};
cout<< "input vector at index -1 is: " << input[-1] <<endl;
使用上面的代码,结果将是:索引-1处的输入是:0.但是,如果我们使用follwoing:
vector<int> input = {1, 2, 3, 4, 17, 117, 517, 997};
cout<< "input vector at index -1 is: " << input.at(-1) <<endl;
结果是:索引-1处的输入是:libc ++ abi.dylib:以类型为std :: out_of_range:vector的未捕获异常终止.
有人可以向我解释原因吗？谢谢.